【发布时间】:2013-05-02 20:23:43
【问题描述】:
我正在用 Java 开发跳棋游戏,但偶然发现了一个问题。 我正在尝试创建的是,当按下棋盘格时,它前面的可用 2 个点应变为灰色 2 秒。
变灰很容易,但是当我希望它在 2 秒后使用 Thread.sleep(2000) 变回时,我注意到它在实际睡眠之前首先在此开关中完成其余的情况(所以它把新鲜的灰色方块立即变回黑色)
出了什么问题?提前致谢!
switch (bord[ypos][xpos]) {
case 0:
break;
case 1:
break;
case 2:
if (bord[ypos + 1][xpos - 1] == 1) {
bord[ypos + 1][xpos - 1] = 4;
}
if (bord[ypos + 1][xpos + 1] == 1) {
bord[ypos + 1][xpos + 1] = 4;
}
repaint();
try {
Thread.sleep(2000);
} catch (InterruptedException e) {
}
if (bord[ypos + 1][xpos - 1] == 4) {
bord[ypos + 1][xpos - 1] = 1;
}
if (bord[ypos + 1][xpos + 1] == 4) {
bord[ypos + 1][xpos + 1] = 1;
}
break;
case 3:
break;
}
用计时器试试(我是新手,所以请不要用力捂脸)
/*
* To change this template, choose Tools | Templates
* and open the template in the editor.
*/
package dammen;
import java.awt.Color;
import java.awt.Dimension;
import java.awt.Graphics;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.awt.event.MouseEvent;
import java.awt.event.MouseListener;
import java.util.logging.Level;
import java.util.logging.Logger;
import javax.swing.JPanel;
import javax.swing.Timer;
/**
*
* @author Boyen
*/
public class Board extends JPanel implements MouseListener {
boolean test;
boolean black = false;
boolean redpiece = false;
boolean bluepiece = true;
Timer timer;
private int[][] bord = {{0, 2, 0, 2, 0, 2, 0, 2},
{2, 0, 2, 0, 2, 0, 2, 0},
{0, 2, 0, 2, 0, 2, 0, 2},
{1, 0, 1, 0, 1, 0, 1, 0},
{0, 1, 0, 1, 0, 1, 0, 1},
{3, 0, 3, 0, 3, 0, 3, 0},
{0, 3, 0, 3, 0, 3, 0, 3},
{3, 0, 3, 0, 3, 0, 3, 0}};
public Board(Dammen parent) {
addMouseListener(this);
timer = new Timer(100,taskPerformer);
timer.setRepeats(false);
}
public void start() {
}
public void paint(Graphics g) {
super.paint(g);
Dimension size = getSize();
for (int i = 0; i < 8; i++) {
for (int j = 0; j < 8; j++) {
switch (bord[i][j]) {
case 0:
g.setColor(Color.WHITE);
break;
case 1:
g.setColor(Color.BLACK);
break;
case 2:
g.setColor(Color.RED);
break;
case 3:
g.setColor(Color.BLUE);
break;
case 4:
g.setColor(Color.gray);
break;
}
g.fillRect((size.width / 8) * j, (size.height / 8) * i, size.width / 8, size.height / 8);
}
}
}
int mouseX, mouseY;
@Override
public void mouseClicked(MouseEvent e) {
mouseX = e.getX();
mouseY = e.getY();
zoekmogelijkespots(mouseX, mouseY);
}
ActionListener taskPerformer = new ActionListener() {
@Override
public void actionPerformed(ActionEvent e) {
}
};
public void zoekmogelijkespots(int mouseX, int mouseY) {
Dimension size = getSize();
System.out.println(mouseX + "," + mouseY);
int xpos;
int ypos;
xpos = (int) (mouseX / (size.width / 8));
ypos = (int) (mouseY / (size.height / 8));
System.out.println(ypos + "," + xpos);
System.out.println(bord[ypos][xpos]);
switch (bord[ypos][xpos]) {
case 0:
break;
case 1:
break;
case 2:
if (bord[ypos + 1][xpos - 1] == 1) {
bord[ypos + 1][xpos - 1] = 4;
}
if (bord[ypos + 1][xpos + 1] == 1) {
bord[ypos + 1][xpos + 1] = 4;
}
repaint();
timer.start();
if (bord[ypos + 1][xpos - 1] == 4) {
bord[ypos + 1][xpos - 1] = 1;
}
if (bord[ypos + 1][xpos + 1] == 4) {
bord[ypos + 1][xpos + 1] = 1;
}
break;
case 3:
break;
}
}
@Override
public void mousePressed(MouseEvent e) {
}
@Override
public void mouseReleased(MouseEvent e) {
}
@Override
public void mouseEntered(MouseEvent e) {
}
@Override
public void mouseExited(MouseEvent e) {
}
}
【问题讨论】:
-
您的游戏是在事件线程还是其他线程上运行?
-
@durron597 线程.sleep(2000);是整个代码中唯一与线程有关的行,如果你想知道的话(这是朋友建议的)
-
不要阻塞 EDT(事件调度线程)——当这种情况发生时,GUI 将“冻结”。而不是调用
Thread.sleep(n)实现单次SwingTimer。有关详细信息,请参阅Concurrency in Swing。 -
据我了解,计时器仅用于重复性任务?这是在行动,不过我可能错了。
-
@Boyen:安德鲁回答了 1139 个摇摆问题,获得了 3373 票。在挥杆方面你可以相信他。顺便说一句,你问的是一个他可能获得 2000 票赞成的问题,因为它每天都会被问两次。
标签: java multithreading swing switch-statement event-dispatch-thread