【发布时间】:2020-12-14 15:08:11
【问题描述】:
我的程序让用户计算两个数字,然后根据用户输入的运算符执行简单的计算。所以我的源代码是:
System.out.print("Enter First Number: ");
int num1 = scanNum.nextInt();
System.out.print("Enter Second Number: ");
int num2 = scanNum.nextInt();
System.out.print("Enter Operator (+, -, * or /): ");
char opt = scanOpt.next().charAt(0);
scanNum.close();
scanOpt.close();
switch (opt)
{
case '+':
float result = num1 + num2;
System.out.println(num1 + " " + opt + " " + num2 + " = " +result);
break;
case '-':
result = num1 - num2;
System.out.println(num1 + " " + opt + " " + num2 + " = " +result);
break;
case '*':
result = num1 * num2;
System.out.println(num1 + " " + opt + " " + num2 + " = " +result);
break;
case '/':
result = num1 / num2;
System.out.println(num1 + " " + opt + " " + num2 + " = " +result);
break;
default:
System.out.println("Invalid Operator!");
break;
它工作得很好,但是每当它将两个数字相除时,例如“6.0 / 4.0”,第十位小数就不会出现。正确的输出应该是:
Enter First Number: 6
Enter Second Number: 4
Enter Operator (+, -, * or /): /
6 / 4 = 1.5
但使用我自己的源代码输出是:
Enter First Number: 6
Enter Second Number: 4
Enter Operator (+, -, * or /): /
6 / 4 = 1.0
【问题讨论】:
-
@Ivar 我已经把数据类型改成了双精度,但是还是不行
-
num1或num2需要为十进制类型。如果您将其中一个转换为float或double,它将起作用。喜欢result = (double)num1 / num2。 -
已经工作了,谢谢!
标签: java switch-statement