续集“字段列表”中的未知列“* .createdAt”

Question

我在“字段列表”中得到一个未知列“userDetails.createdAt” 尝试通过关联获取时。

在没有关联的情况下使用findAll 可以正常工作。

我的代码如下：

var userDetails = sequelize.define('userDetails', {
    userId :Sequelize.INTEGER,
    firstName : Sequelize.STRING,
    lastName : Sequelize.STRING,
    birthday : Sequelize.DATE
});

var user = sequelize.define('user', {
    email: Sequelize.STRING,
    password: Sequelize.STRING
});

user.hasOne(userDetails, {foreignKey: 'userId'});

user.findAll({include: [userDetails] }).success(function(user) {
    console.log(user)
});

Answer 1

在一般配置中这有帮助：

{
  timestamps: true,
}

之后

{
  timestamps: true,
  underscored: true,
}

Answer 2

对于 postgresql：

const sequelize = new Sequelize('postgres://user:pass@url:port/dbname',{ 
    define:{
        timestamps: false
    }
})

不用说，用您的配置值替换 user,pass,url,port 和 dbname 值。

Answer 3

同样的错误，两种解决方法：

1. 创建表时，添加 created_at 和 updated_at 列。

CREATE TABLE `users` (
  `id` int(11) NOT NULL AUTO_INCREMENT COMMENT 'primary key',
  `name` varchar(30) DEFAULT NULL COMMENT 'user name',
  `created_at` datetime DEFAULT NULL COMMENT 'created time',
  `updated_at` datetime DEFAULT NULL COMMENT 'updated time',
  PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4 COMMENT='user';

1. 禁用时间戳

const Project = sequelize.define('project', {
   title: Sequelize.STRING,
   description: Sequelize.TEXT
 },{
   timestamps: false
 })

Answer 4

好吧，也许为时已晚，但你可以在迁移时创建 createdAt、updatedAt

      createdAt: {
        allowNull: false,
        defaultValue: Sequelize.fn('now'),
        type: Sequelize.DATE
      },
      updatedAt: {
        allowNull: false,
        defaultValue: Sequelize.fn('now'),
        type: Sequelize.DATE
      }

我正在使用 express 和 sequelize mysql 然后模型就像正常定义一样 例如：

module.exports = (sequelize, DataTypes) => {
  const Customer = sequelize.define('customer', {
    name: DataTypes.STRING,
    email: DataTypes.STRING,
    phone: DataTypes.TEXT,
    consider: DataTypes.TEXT,
    otherQuestion: DataTypes.TEXT
  }, {})
  return Customer

Answer 5

禁用时间戳 例如：-

const User = sequelize.define('user', {
    firstName : Sequelize.STRING,
    lastName : Sequelize.STRING,
}, {
    timestamps: false
});

Answer 6

在将我们的项目从 laravel 迁移到 featherjs 时，我遇到了同样的错误。表的列名称为 created_at、updated_at 而不是 createdat、updateat。我必须在 Sequelize 模型中使用字段名称映射，如下所示

  const users = sequelize.define('users', {
     id: {
         type: Sequelize.INTEGER,
         primaryKey: true
     },
     createdAt: {
         field: 'created_at',
         type: Sequelize.DATE,
     },
     updatedAt: {
         field: 'updated_at',
         type: Sequelize.DATE,
     },
     ..
     ..
     ..
     ..

Answer 7

我认为错误是您在 sequelize 中启用了时间戳，但您在数据库中的实际表定义不包含时间戳列。

当您执行 user.find 时，它只会执行SELECT user.*，它只会占用您实际拥有的列。但是当你 join 时，joined table 的每一列都会有别名，这会创建以下查询：

SELECT `users`.*, `userDetails`.`userId` AS `userDetails.userId`,`userDetails`.`firstName` AS `userDetails.firstName`,`userDetails`.`lastName` AS `userDetails.lastName`, `userDetails`.`birthday` AS `userDetails.birthday`, `userDetails`.`id` AS `userDetails.id`, `userDetails`.`createdAt` AS `userDetails.createdAt`, `userDetails`.`updatedAt` AS `userDetails.updatedAt` FROM `users` LEFT OUTER JOIN `userDetails` AS `userDetails` ON `users`.`id` = `userDetails`.`userId`;

解决方法是禁用 userDetails 模型的时间戳：

var userDetails = sequelize.define('userDetails', {
    userId :Sequelize.INTEGER,
    firstName : Sequelize.STRING,
    lastName : Sequelize.STRING,
    birthday : Sequelize.DATE
}, {
    timestamps: false
});

或适用于所有型号：

var sequelize = new Sequelize('sequelize_test', 'root', null, {
    host: "127.0.0.1",
    dialect: 'mysql',
    define: {
        timestamps: false
    }
});