创建列表有问题

Question

我制作了一个股票筛选器，提供符合我标准的股票的技术数据，最后，我希望它打印一份符合我标准的股票的简明清单。我尝试使用 append 函数，但它只打印一只股票，相反，我希望它打印每只股票的股票代码，例如'mmm'，...

当前输出如下所示。 嗯 追踪市盈率：17.61 股本回报率：54.34% 收入：32.35B 季度收入增长：-5.00%

---

def scrape(stock_list, interested, technicals):
    for each_stock in stock_list:
        technicals = scrape_yahoo(each_stock)
        condition_1 = float(technicals.get('Return on Equity',0).replace('%','').replace('N/A','-100')) > 25
        condition_2 = float(technicals.get('Trailing P/E',0).replace('N/A','')) > 15
        condition_3 = float(technicals.get('Price/Book (mrq)',0)) <15
        if (condition_1 and condition_2)==True:
            print(each_stock)
            SuggestedStocks = []
            SuggestedStocks.append(each_stock)  
            for ind in interested: 

                print(ind + ": "+ technicals[ind])         
            print("------")
            time.sleep(1)                                                    # Use delay to avoid getting flagged as bot
    #return technicals
    print(SuggestedStocks)


def main():

    stock_list = ['MMM', 'ABT', 'ABBV', 'ABMD', 'ACN', 'ATVI', 'ADBE', 'AMD']
    interested = ['Trailing P/E', 'Return on Equity', 'Revenue', 'Quarterly Revenue Growth']
    technicals = {}

    tech = scrape(stock_list, interested, technicals)
    print(tech)
main()

它只打印符合我条件的最后一只股票的代码：ADBE。

Answer 1

这是因为您在每个循环SuggestedStocks = [] 中重置了建议股票，您应该在循环之外对其进行初始化。