如何根据条件访问类属性

Question

我有下面的对象及其内部对象，并且我已将自定义属性添加到报告所需的属性名称中。

public class Space
{
    public SpaceIdentity SpaceIdentity { get; set; } = new();
    public SpaceGeometry SpaceGeometry { get; set; } = new();
    public AirBalance AirBalance { get; set; } = new();
    public EngineeringChecks EngineeringChecks { get; set; } = new();
}
public class SpaceIdentity
{
    public int ElementId { get; set; } // Not required
    [DisplayNameWithUnits(DisplayName = "Space Number", IsIncludedInReport2 = true)]
    public string Number { get; set; }
    [DisplayNameWithUnits(DisplayName = "Space Name", IsIncludedInReport2 = true, IsIncludedInReport1 = true)]
    public string Name { get; set; }
    [DisplayNameWithUnits(DisplayName = "Room Number", IsIncludedInReport1 = true)]
    public string RoomNumber { get; set; }
    [DisplayNameWithUnits(DisplayName = "Room Name", IsIncludedInReport1 = true)]
    public string RoomName { get; set; }
}

public class SpaceGeometry
{
    public Vertex LocationPoint { get; set; } // this is not required
    [DisplayNameWithUnits(DisplayName = "Space Area", Units = "(ft²)", IsIncludedInReport1 = true)]
    public double FloorArea { get; set; }
}
.....

在这里，我正在构建一个 Excel 报表，我想使用属性显示名称作为该报表的标题列名称。以下是多个报告中使用的一些属性属性信息。我所做的是我添加了一个布尔条件属性，如 (isIncludedInReport1) 并循环遍历 space 的属性并循环遍历内部对象的属性 (SpaceGeometry) 以获取特定的属性名称及其基于的属性值这个布尔条件。

我在这里寻找的是不添加这些布尔属性，有没有办法根据条件访问属性名称。我考虑过添加接口，但这里不可能，因为我有多个内部类，它们的属性需要包含在单个报告中。

谁能告诉我有没有其他方法可以做到这一点？

更新：

   var columnResult = new OrderedDictionary();
    GetReportHeaderColumnName(typeof(Space), columnResult);
    
    public static void GetReportHeaderColumnName(Type type, OrderedDictionary headerNameByUnit)
    {
        var properties = type.GetProperties();
        foreach (var propertyInfo in properties)
        {
            if (propertyInfo.PropertyType.IsClass && !propertyInfo.PropertyType.FullName.StartsWith("System."))
            {
                if (propertyInfo.PropertyType == typeof(Overridable<double>))
                {
                    AddReportHeaderName(headerNameByUnit, propertyInfo);
                }
                else
                {
                    GetReportHeaderColumnName(propertyInfo.PropertyType, headerNameByUnit);
                }
            }
            else
            {
                AddReportHeaderName(headerNameByUnit, propertyInfo);
            }
        }
    }

    protected static void AddReportHeaderName(OrderedDictionary columnResult, PropertyInfo propertyInfo)
    {
        if (propertyInfo.GetCustomAttributes(typeof(DisplayNameWithUnitsAttribute), true).Any())
        {
            var displayNameWithUnitsAttribute = (DisplayNameWithUnitsAttribute)Attribute.GetCustomAttribute(propertyInfo, typeof(DisplayNameWithUnitsAttribute));

            if (displayNameWithUnitsAttribute.IsIncludedInReport2)
            {
                columnResult.Add(displayNameWithUnitsAttribute.DisplayName, displayNameWithUnitsAttribute.Units);
            }
        }
    }

Answer 1

另一种不使用反射的方法是只使用ReportProperty的列表

public record ReportProperty<T>(
    Func<T, string> ValueFunc,
    string DisplayName,
    string? Unit = null
    );

List<ReportProperty<Space>> report1 = new(){
    new( s => s.SpaceIdentity.Number, "Space Number"),
    new( s => s.SpaceIdentity.RoomNumber, "Room Number"),
    new( s => s.SpaceIdentity.RoomName, "Room Name"),
    new( s => s.SpaceGeometry.FloorArea.ToString(), "Floor Area", "Ft2"),
};

Answer 2

您想通过另一种方式实现什么？我假设您想让您的代码可扩展，以便更轻松地添加更多报告。

您还想在类本身上使用属性吗？如果是这样，您可以创建一个新属性，并像这样标记您的属性：

public class SpaceIdentity
{
    public int ElementId { get; set; } // Not required
    [DisplayNameWithUnits(DisplayName = "Space Number")]
    [IncludeInReport(2)]
    public string Number { get; set; }
    
    [DisplayNameWithUnits(DisplayName = "Space Name")]
    [IncludeInReport(1)]
    [IncludeInReport(2)]
    public string Name { get; set; }

    [DisplayNameWithUnits(DisplayName = "Room Number")]
    [IncludeInReport(1)]
    public string RoomNumber { get; set; }

    [DisplayNameWithUnits(DisplayName = "Room Name")]
    [IncludeInReport(1)]
    public string RoomName { get; set; }
}

或者您想将报告与类分开，以便在另一个文件中定义您的报告？如果是这样，也许属性名称的二维列表可以解决问题：

List<List<string>> Report1 = new()
{
    new(){nameof(Space.SpaceIdentity), nameof(SpaceIdentity.Name)},
    new(){nameof(Space.SpaceIdentity), nameof(SpaceIdentity.RoomNumber)},
    new(){nameof(Space.SpaceIdentity), nameof(SpaceIdentity.RoomName)},
    new(){nameof(Space.SpaceGeometry), nameof(SpaceGeometry.FloorArea)}
};