从多个电子表格中收集数据并将其复制到另一个工作表中

Question

我想将数据从一个电子表格复制到另一个电子表格。但 1. 数据在几张纸上 2.只有某些列（只是为了加快速度，不需要所有列）

一开始我使用了以下脚本：

function CopyDataToNewFile() {
  var sss = SpreadsheetApp.openById('0AjN7uZG....'); // sss = source spreadsheet
  var ss = sss.getSheetByName('Monthly'); // ss = source sheet
  //Get full range of data
  var SRange = ss.getDataRange();
  //get A1 notation identifying the range
  var A1Range = SRange.getA1Notation();
  //get the data values in range
  var SData = SRange.getValues();

  var tss = SpreadsheetApp.openById('8AjN7u....'); // tss = target spreadsheet
  var ts = tss.getSheetByName('RAWData'); // ts = target sheet
  //set the target range to the values of the source data
  ts.getRange(A1Range).setValues(SData);

}  

我从user2741那里拿了这个，发在here：

..这一张适用于一张纸。 但现在我不确定如何从更多工作表中获取数据并对其进行实际排序。有没有人知道如何做到这一点？

谢谢大家， 萨沙

如果所有事情都发生在同一个电子表格中，那么这里可以工作

SpreadsheetApp.getActiveSpreadsheet().getSheetByName("SummarySheet").clear();
mergeSheet2("SummarySheet", "123");
mergeSheet2("SummarySheet", "345");
mergeSheet2("SummarySheet", "748");
mergeSheet2("SummarySheet", "293");

function mergeSheet2(targetSheetName, sourceSheetName) {
  var ss = SpreadsheetApp.getActiveSpreadsheet();
  var sourceSheet = ss.getSheetByName(sourceSheetName);
  var lastRow = sourceSheet.getLastRow();
  var lastCol = sourceSheet.getLastColumn();
  var source = sourceSheet.getRange(1,1,lastRow,lastCol); // Error after some iterations: The coordinates or dimensions of the range are invalid. (line 11, file "copy-m.js") -> might be empty spreadsheet
  var destSheet = ss.getSheetByName(targetSheetName);
  var destRange = destSheet.getRange(destSheet.getLastRow()+1,1);
  source.copyTo(destRange, {contentsOnly: true});

}

但由于某种原因，我在使用不同的电子表格时无法运行它 错误：“目标范围和源范围必须在同一个电子表格中”

我试过了：

SpreadsheetApp.getActiveSpreadsheet().getSheetByName("SummarySheet").clear();
SpreadsheetApp.openById('ID');
mergeSheet2("SummarySheet", "123");


function mergeSheet2(targetSheetName, sourceSheetName) {
  var ss = SpreadsheetApp.openById('ID');
  var ssd = SpreadsheetApp.openById('ID');
  var sourceSheet = ss.getSheetByName(sourceSheetName);
  var lastRow = sourceSheet.getLastRow();
  var lastCol = sourceSheet.getLastColumn();
  var source = sourceSheet.getRange(1,1,lastRow,lastCol); // Error after some iterations: The coordinates or dimensions of the range are invalid. (line 11, file "copy-m.js") -> might be empty spreadsheet
  var destSheet = ssd.getSheetByName(targetSheetName);
  var destRange = destSheet.getRange(destSheet.getLastRow()+1,1);
  source.copyTo(destRange, {contentsOnly: true});

有什么想法吗？

Answer 1

解决方案比您尝试的更简单，因为您只想复制值并且知道 copyTo 仅适用于同一个电子表格，只需从源获取值并将其粘贴到目标中，如下所示：

function copyFromSourceToTarget(targetSheetName, sourceSheetName) {
  var ss = SpreadsheetApp.openById('ID');
  var ssd = SpreadsheetApp.openById('ID');
  var sourceSheet = ss.getSheetByName(sourceSheetName);
  var sourceData = sourceSheet.getDataRange().getValues();
  var destSheet = ssd.getSheetByName(targetSheetName);
  destSheet.getRange(destSheet.getLastRow()+1,1,sourceData.length,sourceData[0].length).setValues(sourceData);
}

为了使其更灵活，我建议使用 4 个参数并再次简化代码：

function copyFromSourceToTarget(targetSheetName,targetSsId, sourceSheetName,sourceSsId) {
  var ss = SpreadsheetApp.openById(sourceSsId)getSheetByName(sourceSheetName);
  var ssd = SpreadsheetApp.openById(targetSsId).getSheetByName(targetSheetName);
  var sourceData = ss.getDataRange().getValues();
  ssd.getRange(ssd.getLastRow()+1,1,sourceData.length,sourceData[0].length).setValues(sourceData);
}