在 C# Windows 窗体中对字典进行排序[重复]

Question

我在 c# 中有一个 Windows 窗体应用程序，我正在显示字典。

我要做的是对字典进行排序。

在字典中有文件路径以及字典中有多少次的值。我想对列表进行排序以使出现最多的条目出现在顶部，而出现在底部的条目最少

我不知道从哪里开始。

这是我目前的代码：

    namespace Xml_reader
{
    public partial class Form1 : Form
    {
        Dictionary<string, int> _dictionary = new Dictionary<string, int>();
        public Form1()
        {
            InitializeComponent();
        }

        private void getFile_Click(object sender, EventArgs e)
        {
            FileStream fileStream = null;
            fileStream = new FileStream(@"C:\myProject\svn.xml", FileMode.Open, FileAccess.Read, FileShare.Read); 


            XmlSerializer xmlSerializer = new XmlSerializer(typeof(log) );
            log logInstance;
            lock (xmlSerializer)
            {
                logInstance = (log)xmlSerializer.Deserialize(fileStream);
            }
            _dictionary = CreateDictionary(logInstance);
        }

        private Dictionary<string, int> CreateDictionary(log logInstance)
        {
            Dictionary<string, int> dictionary = new Dictionary<string, int>();
            int commonStringNumber = FindCommonString(logInstance);
            for (int entryIdex = 0; entryIdex < logInstance.logentry.Count(); entryIdex++)
            {

                logLogentry entry = logInstance.logentry[entryIdex];

                for (int pathIdex = 0; pathIdex < entry.paths.Count(); pathIdex++)
                {
                    logLogentryPath path = entry.paths[pathIdex];
                    string filePath = path.Value;


                    if (filePath.Length >= commonStringNumber)
                    {
                        string cutPath = filePath.Substring(commonStringNumber);
                        if (dictionary.ContainsKey(cutPath))
                        {
                            dictionary[cutPath]++;
                        }
                        else
                        {
                            dictionary.Add(cutPath, 1);
                        }
                    }
                }
            }
            return dictionary;
        }

        private static int FindCommonString(log logInstance)
        {
            string fCompare = logInstance.logentry[0].paths[0].Value;
            for (int entryIdex = 0; entryIdex < logInstance.logentry.Count(); entryIdex++)
            {
                logLogentry entry = logInstance.logentry[entryIdex];

                for (int pathIdex = 0; pathIdex < entry.paths.Count(); pathIdex++)
                {
                    logLogentryPath path = entry.paths[pathIdex];
                    string fcheck = path.Value;
                    fCompare = similarString(fCompare, fcheck);


                }

            }
            return fCompare.Length;
        }

        private static string similarString(string fCompare, string fcheck)
        {
            int length = Math.Min(fCompare.Length, fcheck.Length);
            string common = String.Empty;
            for (int i = 0; i < length; i++)
            {

                if (fCompare[i] == fcheck[i])
                {
                    common += fCompare[i];
                }
                else
                {
                    break;
                }
            }
            return common;
        }

        private void converToText(Dictionary<string, int> dictionaryList)
        {
            List<KeyValuePair<string, int>> changesWithValues = dictionaryList.ToList();
            display(changesWithValues);
        }

        private void display(List<KeyValuePair<string, int>> changesWithValues)
        {
            textBox1.Text = String.Join(Environment.NewLine, changesWithValues.Where(kvp => kvp.Key != "").Select(kvp => string.Format("{0} = {1}", kvp.Key, kvp.Value)));
        }

        private void Show_Click(object sender, System.EventArgs e)
        {
            converToText(_dictionary);
        }

Answer 1

你可以试试这个：

List<KeyValuePair<string, int>> myList = _dictionary.ToList();

myList.Sort((firstPair,nextPair) =>
    {
        return firstPair.Value.CompareTo(nextPair.Value);
    }
);

---

让我们做一些测试。使用此代码：

_dictionary.Add("Toto", 33);
_dictionary.Add("Tutu", 22);
_dictionary.Add("Pouet", 2);
_dictionary.Add("Pouetr", 57);


List<KeyValuePair<string, int>> myList = _dictionary.ToList();

myList.Sort((firstPair, nextPair) => firstPair.Value.CompareTo(nextPair.Value));
myList.Reverse();

foreach (KeyValuePair<string, int> keyValuePair in myList)
{
    Console.Out.WriteLine(keyValuePair.Value + " " + keyValuePair.Key);
}

我明白了：

57 Pouetr
33 Toto
22 Tutu
2 Pouet

所以，从技术上讲，它正在工作......