【发布时间】:2013-04-03 08:54:26
【问题描述】:
我已成功将DataTable 绑定到WPF with MVVM 中的DataGrid 控件。 (我在viewmodel中定义了DataTable。)
然后我定义了一个DataRowView类型的属性并绑定到DataGrid控件的SelectedItem属性。
我可以通过它获得选定的项目。但我试图设置选定的项目,但我找不到办法。谁能帮我弄清楚。
view
<Window x:Class="Pivot.MainWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:vm="clr-namespace:Pivot.ViewModels"
Title="MainWindow" Height="350" Width="525">
<Grid>
<Grid.DataContext>
<vm:MainViewModel />
</Grid.DataContext>
<DataGrid
ItemsSource="{Binding SizeQuantityTable}"
AutoGenerateColumns="True"
SelectedValue="{Binding SelectedRow}"
Margin="0,0,0,120" />
</Grid>
</Window>
View Model
public class MainViewModel : ViewModelBase
{
#region Declarations
private DataTable sizeQuantityTable;
private DataRowView selectedRow;
#endregion
#region Properties
/// <summary>
/// Gets or sets the size quantity table.
/// </summary>
/// <value>The size quantity table.</value>
public DataTable SizeQuantityTable
{
get
{
return sizeQuantityTable;
}
set
{
sizeQuantityTable = value;
NotifyPropertyChanged("SizeQuantityTable");
}
}
/// <summary>
/// Gets or sets the selected row.
/// </summary>
/// <value>The selected row.</value>
public DataRowView SelectedRow
{
get
{
return selectedRow;
}
set
{
selectedRow = value;
NotifyPropertyChanged("SelectedRow");
}
}
#endregion
#region Constructors
/// <summary>
/// Initializes a new instance of the <see cref="MainViewModel"/> class.
/// </summary>
public MainViewModel()
{
this.SizeQuantityTable = new DataTable();
DataColumn sizeQuantityColumn = new DataColumn();
sizeQuantityColumn.ColumnName = "Size Quantity";
this.SizeQuantityTable.Columns.Add(sizeQuantityColumn);
DataColumn sColumn = new DataColumn();
sColumn.ColumnName = "S";
this.SizeQuantityTable.Columns.Add(sColumn);
DataColumn mColumn = new DataColumn();
mColumn.ColumnName = "M";
this.SizeQuantityTable.Columns.Add(mColumn);
DataRow row1 = this.SizeQuantityTable.NewRow();
row1[sizeQuantityColumn] = "Blue";
row1[sColumn] = "12";
row1[mColumn] = "15";
this.SizeQuantityTable.Rows.Add(row1);
DataRow row2 = this.SizeQuantityTable.NewRow();
row2[sizeQuantityColumn] = "Red";
row2[sColumn] = "18";
row2[mColumn] = "21";
this.SizeQuantityTable.Rows.Add(row2);
DataRow row3 = this.SizeQuantityTable.NewRow();
row3[sizeQuantityColumn] = "Green";
row3[sColumn] = "24";
row3[mColumn] = "27";
this.SizeQuantityTable.Rows.Add(row3);
DataRow row4 = this.SizeQuantityTable.NewRow();
row4[sizeQuantityColumn] = "Yellow";
row4[sColumn] = "30";
row4[mColumn] = "33";
this.SizeQuantityTable.Rows.Add(row4);
}
#endregion
}
【问题讨论】:
-
不能使用DataTable绑定DataGrid的最佳解决方案,制作Dto并使用Dto列表绑定DataGrid,并绑定Dto类型属性与SelectedItem
-
添加 Mode=TwoWay 并使用 SelectedItem 而不是 SelectedValue
-
我同时使用了 SelectedValue 和 SelectedItem。但没有任何效果。
-
@Jignesh Raj:我的主要目标是
programmatically将列添加到数据网格。我可以从数据库only中实现它。所以我只想要数据表中的解决方案。 -
你在你的问题中说我正在使用 MVVM 所以最好的解决方案是创建 Dto 而不是 DataTable 并绑定 SelectedItem 属性而不是 Selected Value 属性
标签: wpf mvvm datagrid datatable