从 API 响应中检索数据点答案

【问题标题】：Retrieving data poin from API response从 API 响应中检索数据点
【发布时间】：2017-09-06 21:23:46
【问题描述】：

我拼凑了一些 PHP 代码，允许我从 Yelp API v.3 获取业务数据

$postData = "grant_type=client_credentials&".
    "client_id=MyClientIDl94gqHAg&".
    "client_secret=SomEcoDehIW09e6BGuBi4NlJ43HnnHl4S7W5eoXUkB";


// GET TOKEN
$curl = curl_init();

//set the url
curl_setopt($curl,CURLOPT_URL, "https://api.yelp.com/oauth2/token");
//tell curl we are doing a post
curl_setopt($curl,CURLOPT_POST, TRUE);
//set post fields
curl_setopt($curl,CURLOPT_POSTFIELDS, $postData);
//tell curl we want the returned data
curl_setopt($curl,CURLOPT_RETURNTRANSFER, TRUE);
$result = curl_exec($curl);

if($result){
    $data = json_decode($result);
}

// GET RESTAURANT INFO
curl_setopt_array($curl, array(
    CURLOPT_URL => "https://api.yelp.com/v3/businesses/north-india-restaurant-san-francisco",
    CURLOPT_RETURNTRANSFER => true,
    CURLOPT_ENCODING => "",
    CURLOPT_MAXREDIRS => 10,
    CURLOPT_TIMEOUT => 30,
    CURLOPT_HTTP_VERSION => CURL_HTTP_VERSION_1_1,
    CURLOPT_CUSTOMREQUEST => "GET",
    CURLOPT_HTTPHEADER => array(
        "authorization: Bearer ".$data->access_token
    ),
));

$response = curl_exec($curl);
$err = curl_error($curl);

//close connection
curl_close($curl);

if ($err) {
    echo "cURL Error #:" . $err;
} else {
    echo $response;
}

输出如下所示：

{“id”：“north-india-restaurant-san-francisco”，“name”：“北印度餐厅”，“image_url”：“https://s3-media2.fl.yelpcdn.com/bphoto/fIgAIMHGfWRF3I0JmagQ7A/o.jpg”，“is_claimed”：true，“is_closed”：假，“url”：“https://www.yelp.com/biz/north-india-restaurant-san-francisco?adjust_creative=qG_bVdazAjjAO1l94gqHAg&utm_campaign=yelp_api_v3&utm_medium=api_v3_business_lookup&utm_source=qG_bVdazAjjAO1l94gqHAg”，“电话”：“+14153481234”，“display_phone”：“（415）348-1234”，“review_count”：857，“类别”：[{“别名”： “indpak”，“title”：“Indian”}]，“rating”：4.0，“location”：{“address1”：“123 Second St”，“address2”：“”，“address3”：“”，“城市”：“旧金山”，“邮政编码”：“94105”，“国家”：“美国”，“州”：“CA”，“display_address”：[“123 Second St”，“旧金山，CA 94105” ]，“cross_streets”：“”}，“坐标”：{“纬度”：37.787789124691，“经度”：-122.399305736113}，“照片”：[“https://s3-media1.fl.yelpcdn.com/bphoto/howYvOKNPXU9A5KUahEXLA/o.jpg”，“https://s3-media2.fl.yelpcdn.com/bphoto/I-CX8nioj3_ybAAYmhZcYg/o.jpg”，“https://s3-media3.fl.yelpcdn.com/bphoto/uaSNfzJUiFDzMeSCwTcs-A/o.jpg "], "价格": "$$", "小时": [{"open": [{"is_overnight": false, "start": "1000", "end": "2300", "day": 0}，{“is_overnight”：false，“start”：“1000”，“end”：“2300”，“day”：1}，{“is_overnight”：false，“start”：“1000”，“end ": "2300", "day": 2}, {"is_overnight": false, "start": "1000", "end": "2300", "day": 3 }，{“is_overnight”：假，“开始”：“1000”，“结束”：“0000”，“天”：4}，{“is_overnight”：假，“开始”：“1000”，“结束” : "0000", "day": 5}, {"is_overnight": false, "start": "1000", "end": "2300", "day": 6}], "hours_type": "REGULAR" , "is_open_now": true}], "transactions": ["delivery", "pickup"]}

例如，我如何检索周五的营业时间？日期是 0 - 6，周一 - 周日。

【问题讨论】：

标签： php

【解决方案1】：

您解析 json 数据并遍历条目：

function getOpeningHoursForDay($data,$day){
    $open_hours = $data['hours'][0]['open'];
    $n = count($open_hours);

    for($i=0;$i<$n;$i++){
        if($open_hours[$i]['day']==$day) // check if day matches
            return $open_hours[$i];
    }
    return null; // no matching day found, return null
}

function formatOpeningHour($hour){
    return substr($hour,0,2).':'.substr($hour,2); // convert 2300 to 23:00
}


$data = json_decode($response,true);
$friday_hours = getOpeningHoursForDay($data,4);
if(isset($friday_hours)){
    echo 'opened ' . formatOpeningHour($friday_hours['start']) . ' - ' .formatOpeningHour($friday_hours['end']);
}else{
    echo 'closed';
}

【讨论】：