ES6 JavaScript 类

Question

有没有一种方法可以创建一个类，并且在该类中，构造函数方法从其他类传入两个不同的对象，以及一些其他信息。例如，假设我有三个类，一个 Statistics 类、一个 Attributes 类和一个 Character 类。它们看起来像这样：

class Statistics {
    constructor(stren, dex, wis, cha, armorClass, hitPoints) {
        this._stren = stren;
        this._dex = dex;
        this._wis = wis;
        this._cha = cha;
        this._armorClass = armorClass;
        this._hitPoints = hitPoints;
    }
}

class Attributes {
    constructor(name, race, sex, level, height, weight, speed) {
        this._name = name;
        this._race = race;
        this._sex = sex;
        this._level = level;
        this._height = height;
        this._weight = weight;
        this._speed = speed;
    }
}

由于 Character 类的构造函数将有 13+ 个参数，我认为将它们分成其他类比编写具有 13+ 个参数的构造函数要好。那么有没有办法做类似的事情：

class Character {
    constructor(Statistics statistic, Attributes attributes) {
        .....
    }
}

编辑：不，这不是那个问题的重复，人们在说问题重复之前是否真的阅读过所问的内容？

Answer 1

请记住，类只是语法糖，因此您可以使用 Object.defineProperty 添加到 Character 原型并制作自己的 getter。

编辑：用循环将其干燥。

class Statistics {
    constructor(stren, dex, wis, cha, armorClass, hitPoints) {
        this._stren = stren;
        this._dex = dex;
        this._wis = wis;
        this._cha = cha;
        this._armorClass = armorClass;
        this._hitPoints = hitPoints;
    }
}

class Attributes {
    constructor(name, race, sex, level, height, weight, speed) {
        this._name = name;
        this._race = race;
        this._sex = sex;
        this._level = level;
        this._height = height;
        this._weight = weight;
        this._speed = speed;
    }
}

class Character {
    constructor(statistics, attributes) {
        this.buildGetters(attributes)
        this.buildGetters(statistics)
      }
      
      buildGetters(obj) {
        for (let attr in obj){
          Object.defineProperty(Character.prototype, attr.replace("_", ""), {
            get: function() {
              return obj[attr]
            }
          })
        }
      }
}


const stats = new Statistics()
const attr = new Attributes("Mike")
const mike = new Character(stats, attr)
console.log(mike.name);