如何从具有字符串值的对象数组中获取总数？

Question

输入：

[
  {
    15: "3.0",
    20: "6.0",
    34: "4.0,
    Dosis: "First",
    Sex: "Male"
  },
  {
    15: "3.0",
    27: "6.0",
    32: "4.0,
    Dosis: "Second",
    Sex: "Male"
  },
  {
    15: "",
    23: "12.0",
    44: "7.0,
    Dosis: "First",
    Sex: "Female"
  },
  {
    15: "3.0",
    70: "6.0",
    54: "34.0,
    Dosis: "Second",
    Sex: "Female"
  },
]

我正在尝试重新排列一些数据，因为我需要在 JavaScript 中制作饼图。

我做了一些事情，但经历了许多过程，也许有更好的方法来做到这一点

这是我的实际数据（类似）：

我只需要每个剂量和性别的全部数据的总数。 我还需要将“字符串编号”更改为数字。

预期输出：

[
  {
    totalFirstMale: 13
    Dosis: "First",
    Sex: "Male"
  },
  {
    totalSecondMale: 13
    Dosis: "Second",
    Sex: "Male"
  },
  {
    totalFirstFemale: 19
    Dosis: "First",
    Sex: "Female"
  },
  {
    totalSecondFemale: 43
    Dosis: "Second",
    Sex: "Female"
  },
]

PD： 对象键值表示年龄，但我只需要每个性别的总数。

原始数组包含结构相同的 4 个关键性别（男性、女性、未知、双性人）。

我尝试过这样的事情：

    const maleData= json.filter(el => el.Sex === 'Male')
    const femaleData= json.filter(el => el.Sex === 'Female')

    const dataMaleFirst = maleData[0]
    const dataMaleSecond = maleData[1]
    const dataFemaleFirst = femaleData[0]
    const dataFemaleSecond = femaleData[1]

    const objValueFirstMale = Object.values(dataMaleFirst).map(el => el * 1)
    const objValueSecondMale = Object.values(dataMaleSecond).map(el => el * 1)

    const objValueFirstFemale = Object.values(dataFemaleFirst).map(el => el * 1)
    const objValueSecondFemale = Object.values(dataFemaleSecond).map(el => el * 1)

    let totalFirstMale = 0
    let totalSecondMale = 0
    let totalFirstFemale = 0
    let totalSecondFemale = 0

    for (let i = 0; i < objValueFirstMale.length || i < objValueSegundasHombre.length; i++) {
        !isNaN(objValueFirstMale[i]) ? totalFirstMale += objValueFirstMale[i] : 0
        !isNaN(objValueSecondMale[i]) ? totalSecondMale += objValueSecondMale[i] : 0
    }

    for (let i = 0; i < objValueFirstFemale.length || i < objValueSecondFemale.length; i++) {
        !isNaN(objValueFirstFemale[i]) ? totalFirstFemale += objValueFirstFemale[i] : 0
        !isNaN(objValueSecondFemale[i]) ? totalSecondFemale += objValueSecondFemale[i] : 0
    }
    
    return {
        firstMaleDosis: totalFirstMale,
        secondMaleDosis: totalSecondMale,
        totalMaleDosis: totalFirstMale + totalSecondMale,
        firstFemaleDosis: totalFirstFemale,
        secondFemaleDosis: totalSecondFemale ,
        totalFemaleDosis: totalFirstFemale + totalSecondFemale 
    }

看起来很糟糕我知道哈哈哈，现在我必须添加未知数据和双性人数据。因此，再次执行所有这些“逻辑”可能会有问题>_>。

非常感谢您的帮助！

Answer 1

您没有提及您使用的是哪种语言。 此解决方案适用于 javascript。

 const data = [
  {
    15: "3.0",
    20: "6.0",
    34: "4.0",
    Dosis: "First",
    Sex: "Male"
  },
  {
    15: "3.0",
    27: "6.0",
    32: "4.0",
    Dosis: "Second",
    Sex: "Male"
  },
  {
    15: "",
    23: "12.0",
    44: "7.0",
    Dosis: "First",
    Sex: "Female"
  },
  {
    15: "3.0",
    70: "6.0",
    54: "34.0",
    Dosis: "Second",
    Sex: "Female"
  },
]
  const output = data.map(el => {
    const countedKey = Object.keys(el).filter(item => !['Dosis', 
    'Sex'].includes(item));
    let totalCount = 0;
    countedKey.forEach(cnt => {
      if(!isNaN(parseInt(el[cnt]))) totalCount += parseInt(el[cnt]);
    });
    return { [`total${el.Dosis}${el.Sex}`]: totalCount, Dosis: el.Dosis, Sex: 
   el.Sex }
  });

console.log(output);

Answer 2

可以试试这个：

const data = [
  {
    15: "3.0",
    20: "6.0",
    34: "4.0",
    Dosis: "First",
    Sex: "Male"
  },
  {
    15: "3.0",
    27: "6.0",
    32: "4.0",
    Dosis: "Second",
    Sex: "Male"
  },
  {
    15: "",
    23: "12.0",
    44: "7.0",
    Dosis: "First",
    Sex: "Female"
  },
  {
    15: "3.0",
    70: "6.0",
    54: "34.0",
    Dosis: "Second",
    Sex: "Female"
  },
];
let output = [];
data.forEach(e => {

  const tempElem = {...e};
  delete tempElem['Dosis'];
  delete tempElem['Sex'];
  output.push({
    Dosis: e['Dosis'],
    Sex: e['Sex'],
    [`total${e.Dosis}${e.Sex}`]: Object.values(tempElem).filter(e => e !== '').reduce((a, b) => parseFloat(a) + parseFloat(b), 0)
  });
});
console.log(output);

Answer 3

我终于做到了：

let output = data.map(({ Dosis, Sex, ...restOfData }) => {
    const countedKey = Object.keys(restOfData)
    
    let totalCount = 0

    countedKey.forEach(el => {
        totalCount += +restOfData[el]
    })

    return {
        Dosis,
        Sex,
        [`total${Dosis}${Sex}`]: totalCount
    }
})

谢谢大家为我解惑！！