DB2/SQL 聚合之前的工作日

Question

我有一个查询，目前从预先填充的表中获取每日记录与每周数的对比：

   SELECT Employee,
          sum(case when category = 'Shirts' then daily_total else 0 end) as Shirts_DAILY,
          sum(case when category = 'Shirts' then weekly_quota else 0 end) as Shirts_QUOTA, -- this is a static column, this number is the same for every record
          sum(case when category = 'Shoes' then daily_total else 0 end) as Shoes_DAILY,
          sum(case when category = 'Shoes' then weekly_quota else 0 end) as Shoes_QUOTA, -- this is a static column, this number is the same for every record
          CURRENT_DATE as DATE_OF_REPORT
   from SalesNumbers
   where date_of_report >= current_date
   group by Employee;

每晚在脚本中运行并返回如下记录：

   Employee   |   shirts_DAILY   |   shirts_QUOTA   |   Shoes_DAILY   |   Shoes_QUOTA   |   DATE_OF_REPORT
   --------------------------------------------------------------------------------------------------------
   123                15                  75                14                85              2019-08-30

这是上周五晚间报道的记录。我正在尝试找到一种方法为每个类别添加一个列，该列将在前一个工作日（从周日到周六作为一周）每个类别的每日总数（shirts_DAILY，shoes_DAILY）的总和除以该类别的配额（衬衫_QUOTA，鞋子_QUOTA）。

例如，这里是从星期日到星期四的记录

   Employee   |   shirts_DAILY   |   shirts_QUOTA   |   Shoes_DAILY   |   Shoes_QUOTA   |   DATE_OF_REPORT
   --------------------------------------------------------------------------------------------------------
   123                15                 75                16                85              2019-08-25
   123                4                  75                2                 85              2019-08-26
   123                8                  75                6                 85              2019-08-27
   123                2                  75                8                 85              2019-08-28
   123                15                 75                14                85              2019-08-29

通过我的新更改，我希望周五晚上的记录将周日到周四的每日记录的总和除以配额（包括周五的每日总和）

周五晚上的新栏目记录：

   Employee   |   shirts_DAILY   |   shirts_QUOTA   |   shirtsPercent   |   Shoes_DAILY   |   Shoes_QUOTA   |   shoesPercent   |   DATE_OF_REPORT
   -----------------------------------------------------------------------------------------------------------------------------------------------
   123                2                 75                    61.3               7                85              62.4                2019-08-30

因此，周五的跑步为 46/75 的衬衫添加了 15,4,8,2,15,2，为 53/85 的鞋子添加了7,14,8,6,2,16。因此，如果有意义的话，就是前一周的每日总和，包括现在的每日总和。

我实现这一目标的最佳方式是什么？

Answer 1

    SELECT Employee,
    sum(case when category = 'Shirts' and  date_of_report >=  current date then 
        daily_total else 0 end) as Shirts_DAILY,
    sum(case when category = 'Shirts' and  date_of_report >=  current date then
       weekly_quota else 0 end) as Shirts_QUOTA,
    ( sum(case when category = 'Shirts' then 
        daily_total else 0 end) * 100 ) /
    ( sum(case when category = 'Shirts' and  date_of_report >=  current date then
       weekly_quota else 0 end) ) as Shirts_PERCENT,
    CURRENT_DATE as DATE_OF_REPORT
    from SalesNumbers
    where date_of_report >= ( current date - ( dayofweek(current date) - 1 ) days )
    group by Employee