【发布时间】:2013-10-12 16:23:18
【问题描述】:
有什么更好的方法
using (var db = new SmartContext())
{
var MyQuery = from idr in db.ID_SB
join tk in db.Track_SB on idr.MB_Track_ID equals tk.MB_TrackID
join talr in db.Track_Album_Reln on tk.MB_TrackID equals talr.MB_Track_ID
join tal in db.Album_SB on talr.MB_AlbumID equals tal.MB_Release_ID
orderby idr.Last_played descending
select new
{
mb = tk.MB_TrackID,
Hash = idr.Hash,
Title = tk.Title,
Album = tal.Album_Name,
Times_Played = idr.Times_played,
Last_Played = idr.Last_played
};
string artist = "";
var list = new[] { new { Hash = "", Title = "", Album = "", Artist = "", Times_Played = "", Last_Played = ""}}.ToList();
list.Clear();
foreach (var q in MyQuery)
{
int i = 0;
var art = db.Track_Artist_Reln.Where(a => a.MB_Track_ID == q.mb);
foreach (var a in art)
{
var tart = db.Artist_SB.Where(ar => ar.MB_Artist_ID == a.MB_ArtistID).Select(ar => ar.Artist_Name);
foreach (var tar in tart)
{ if (i != 0) { artist = artist + ", " + tar; } else { artist = tar; i++; } }
}
list.Add(new
{
Hash = q.Hash.ToString(),
Title = q.Title.ToString(),
Album = q.Album.ToString(),
Artist = artist.ToString(),
Times_Played = q.Times_Played.ToString(),
Last_Played = q.Last_Played.ToString(),
});
}
ListView1.ItemsSource = list;
}
有没有更好的方法,因为它消耗大量时间
这段代码可以达到目的
在这我想检索
- 散列
- 标题
- 专辑名
- 艺术家(包含单行字段艺术家中该歌曲的所有艺术家)
- 播放次数
- 上次播放
我能得到的一切都是通过加入除了艺术家姓名之外的所有东西
有很多可能的关系 主表 ID_SB、Track_SB、Album_SB、Artist_SB 其他是存储两个表的主键的关系
【问题讨论】:
-
一个快速的改进方法是将两个 foreach 循环中的嵌套 db 查询移动到主查询中,方法是在您的第一个查询中将其作为集合返回。这将导致它对数据库的访问次数减少很多。
-
你也应该去掉 *_Reln 表,EF 多年来一直直接支持多对多关系。