php/mysql - while 循环 ..pass 结果在数组中？

Question

我的标题令人困惑..对此感到抱歉..无论如何..请查看我的代码：

<?php
include('../connectDB.php'); //connect to db

echo '{ ';
    echo '"success": 1, ';
        echo '"result": [ ';
            $result = mysql_query("SELECT * FROM roominventory");
            while($row = mysql_fetch_array($result)) { //start while
                $getId = $row['id']; //get value
                $getRoomId = $row['room'];

                echo '{ ';
                    $ar = $row['arrival']; //assign value to variable
                    $dep = $row['departure'];

                    $date = str_replace('-', '/', $ar); //format the date
                    $formatArr =  date('m/d/Y', strtotime($date));

                    $date2 = str_replace('-', '/', $dep); //format the date
                    $formatDep =  date('m/d/Y', strtotime($date2));

                    $mSt = strtotime($formatArr) * 1000; //convert to milliseconds
                    $mEd = strtotime($formatDep) * 1000;

                    echo '"id": ' . '"' . $getId. '"' . ', ';

                    $resulta = mysql_query("SELECT * FROM rooms_amenities WHERE id='$getRoomId'");
                    while($rowa = mysql_fetch_array($resulta)) {
                        $getName = $rowa['name'];
                    }

                    echo '"title": ' . '"' . $getName . '"' . ', ';
                    echo '"url": ' . '"' . 'http://example.com' . '"' . ', ';
                    echo '"class": ' . '"' . 'event-warning' . '"' . ', ';
                    echo '"start": ' . '"' . $mSt . '"' . ', '; //echo the converted date
                    echo '"end": ' . '"' . $mEd . '" ';
                echo '} ';
                echo ', '; //comma (should only in between entries and not in the very end of the very last entry)
            } //end while
    echo '] ';
echo '}';
?>

现在这是文件的结果：

{ "success": 1, "result": [ { "id": "254", "title": "Standard Room 202", "url": "exampledotcom", "class": "event-warning ", "开始": "1470693600000", "结束": "1471384800000" } ] }

没问题。现在，问题是当我的数据库中的表中有超过 1 行时，结果会变成这样：

{ "success": 1, "result": [ { "id": "255", "title": "Standard Room 201", "url": "exampledotcom", "class": "event-warning "，"开始"："1471903200000"，"结束"："1472076000000" }，{"id"："256"，"title"："标准房间 202"，"url"："exampledotcom"，"class"： “事件警告”，“开始”：“1471903200000”，“结束”：“1472076000000”}，]}

注意最后一个条目“1472076000000”处的“逗号”},] }

我想要/预期的结果应该是这样的：

{ "success": 1, "result": [ { "id": "255", "title": "Standard Room 201", "url": "exampledotcom", "class": "event-warning ", "start": "1471903200000", "end": "1472076000000" }, { "id": "256", "title": "标准房 202", "url": " exampledotcom”，“class”：“事件警告”，“start”：“1471903200000”，“end”：“1472076000000”}]}

注意第一个条目之后和第二个条目之间的“逗号” { "id: "...}, { "id: "...} 并且最后一个条目之后没有逗号。

我试图在 while 循环的外部/结尾回显逗号。但结果，逗号只在最后一个条目，没有中间

如果到达最后一行，那么最后一个条目不应该有逗号。我不知道我怎样才能得到想要的结果。

还有其他方法/方法吗？喜欢使用数组/json_encode？ ..但我不知道该怎么做

Answer 1

您可以为此使用 json_encode 来获得正确的 json 输出 或者 您可以使用这种技术摆脱这个“，”（逗号）。

//first use an variable $cnt=0;
//then check into the while loop
//whether the $cnt==0 then not to put the , before the making of an entry 
//for example,
<?php
include('../connectDB.php'); //connect to db
$cnt=0;

echo '{ ';
echo '"success": 1, ';
    echo '"result": [ ';
        $result = mysql_query("SELECT * FROM roominventory");
        while($row = mysql_fetch_array($result)) { //start while
            $getId = $row['id']; //get value
            $getRoomId = $row['room'];
            if($cnt==0)
            {
                 echo '{ ';
            }
            else
            {
                 echo ',{';
            }
                $ar = $row['arrival']; //assign value to variable
                $dep = $row['departure'];

                $date = str_replace('-', '/', $ar); //format the date
                $formatArr =  date('m/d/Y', strtotime($date));

                $date2 = str_replace('-', '/', $dep); //format the date
                $formatDep =  date('m/d/Y', strtotime($date2));

                $mSt = strtotime($formatArr) * 1000; //convert to milliseconds
                $mEd = strtotime($formatDep) * 1000;

                echo '"id": ' . '"' . $getId. '"' . ', ';

                $resulta = mysql_query("SELECT * FROM rooms_amenities WHERE id='$getRoomId'");
                while($rowa = mysql_fetch_array($resulta)) {
                    $getName = $rowa['name'];
                }

                echo '"title": ' . '"' . $getName . '"' . ', ';
                echo '"url": ' . '"' . 'http://example.com' . '"' . ', ';
                echo '"class": ' . '"' . 'event-warning' . '"' . ', ';
                echo '"start": ' . '"' . $mSt . '"' . ', '; //echo the converted date
                echo '"end": ' . '"' . $mEd . '" ';
            echo '} ';
            //echo ', '; //comma (should only in between entries and not in the very end of the very last entry)
           $cnt=1;
        } //end while
echo '] ';
echo '}';

Answer 2

您可以使用 json_encode 轻松获得该输出。试试这段代码，它应该适合你。

<?php
include('../connectDB.php'); //connect to db

$result = mysql_query("SELECT * FROM roominventory");
while($row = mysql_fetch_array($result)) 
{ //start while
    $getId = $row['id']; //get value
    $getRoomId = $row['room'];

    $ar = $row['arrival']; //assign value to variable
    $dep = $row['departure'];

    $date = str_replace('-', '/', $ar); //format the date
    $formatArr =  date('m/d/Y', strtotime($date));

    $date2 = str_replace('-', '/', $dep); //format the date
    $formatDep =  date('m/d/Y', strtotime($date2));

    $mSt = strtotime($formatArr) * 1000; //convert to milliseconds
    $mEd = strtotime($formatDep) * 1000;

    $resulta = mysql_query("SELECT * FROM rooms_amenities WHERE id='$getRoomId'");

    while($rowa = mysql_fetch_array($resulta))
    {
        $getName = $rowa['name'];
    }

    $new_list= array('id'=>$getId,'title'=>$getName,'url'=>'http://example.com','class'=>'event-warning','start'=>$mSt,'end'=>$mEd);
    $response = array("success"=>1,"result"=>$new_list);    
}
echo json_encode($response);
?>

你可以得到你在问题中显示的输出..谢谢

Answer 3

$result = mysql_query("SELECT * FROM roominventory");
$jsonData = '';
while($row = mysql_fetch_array($result)) { //start while
    $jsonData .= json_encode($row);
}
echo $jsonData;

试试这个。