遍历数组数组中的每个对象找到 id，将其与数组中的另一个对象匹配并将它们连接在一起

Question

所以我有一个名为“products”的数组，其中包含对象，每个对象都有一个唯一的 ID。我还有另一个名为“productsAdditionalInfo”的数组，其中包含与“products”相关的附加信息，并且每个对象都有一个与“products”数组中的一个对象匹配的 owner_id。 'productsAdditionalInfo' 可能在一个数组中包含许多对象，但相对于该数组，它始终具有相同的 owner_id。

我正在尝试遍历“productsAdditionalInfo”数组，获取“owner_id”并将其与 products 数组中的“id”匹配，然后将命名空间添加为键，将值添加为值，然后将其作为新的返回大批。但是，看来我被困在第一个障碍上。我在控制台中得到“持续时间”的第一个键，然后得到未定义的“命名空间”。

我希望这是有道理的，如果不是我已经注释掉了一个应该如何的例子。我很感激任何帮助。

编辑：有些人建议这与another question 相似/相同，您将它们合并在一起，但我相信我的问题是不同的，因为我并没有将它们完全合并在一起只是某些信息。

let products = [ {id: 102, type: "toy"}, {id: 245, type: "food"}, {id: 312, type: "clothes"} ]

let productsAdditionalInfo = [ 
  [{namespace: "Duration", value: 5, owner_id: 245}, {namespace: "effect", value: "Tail", owner_id: 245}], 
  [{namespace: "Supplier", owner_id: 312, value: "rev"}], 
  [{namespace: "amount", value: 0, owner_id: 102}, {namespace: "effect", value: "plush", owner_id: 102}] 
]

$.each(productsAdditionalInfo, function( index, product ) {
  console.log( product[index].namespace );
});


// let whatItShouldBe = [ {id: 102, type: "toy", amount: 0, effect: "plush" }, {id: 245, type: "food", Duration: 5, effect: "Tail"}, {id: 312,  type: "clothes", Supplier: "rev"} ]

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Answer 1

实现此目的的一种方法是遍历每个产品，根据owner_id 检索关联的productAdditionsInfo。从那里您可以从添加创建一个对象并将两者合并在一起，如下所示：

let products = [{id: 102, type: "toy"}, {id: 245, type: "food"}, {id: 312, type: "clothes"}]
let productsAdditionalInfo = [ 
  [{namespace: "Duration", value: 5, owner_id: 245}, {namespace: "effect", value: "Tail", owner_id: 245}], 
  [{namespace: "Supplier", owner_id: 312, value: "rev"}], 
  [{namespace: "amount", value: 0, owner_id: 102}, {namespace: "effect", value: "plush", owner_id: 102}] 
]

let merged = products.map(p => {
  var info = productsAdditionalInfo.filter(i => i[0].owner_id == p.id)[0].map(i => ({ [i.namespace]: i.value }));
  info.push(p);
  return Object.assign(...info);
});

console.log(merged);

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这是假设productsAdditionalInfo 中的二级数组总是由相同的owner_id 分组。

Answer 2

let products = [ {id: 102, type: "toy"}, {id: 245, type: "food"}, {id: 312, type: "clothes"} ]

let productsAdditionalInfo = [ 
  [{namespace: "Duration", value: 5, owner_id: 245}, {namespace: "effect", value: "Tail", owner_id: 245}], 
  [{namespace: "Supplier", owner_id: 312, value: "rev"}], 
  [{namespace: "amount", value: 0, owner_id: 102}, {namespace: "effect", value: "plush", owner_id: 102}] 
]

const flatPAI = productsAdditionalInfo.flat();

console.log(
products.map( p => 
  Object.assign(p,
    ...flatPAI.filter(
         info => info.owner_id == p.id
       ).map(
         info => ({[info.namespace]: info.value})))
)
);



// let whatItShouldBe = [ {id: 102, type: "toy", amount: 0, effect: "plush" }, {id: 245, type: "food", Duration: 5, effect: "Tail"}, {id: 312,  type: "clothes", Supplier: "rev"} ]

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