【发布时间】:2015-03-29 18:18:36
【问题描述】:
我正在使用 Instagram PHP API 来获取 Instagram 中特定标签的所有图像/帖子。
这是我的代码:
<?PHP
function callInstagram($url)
{
$ch = curl_init();
curl_setopt_array($ch, array(
CURLOPT_URL => $url,
CURLOPT_RETURNTRANSFER => true,
CURLOPT_SSL_VERIFYPEER => false,
CURLOPT_SSL_VERIFYHOST => 2
));
$result = curl_exec($ch);
curl_close($ch);
return $result;
}
$tag = "bulgaria";
$client_id = "1e0f576fbdb44e299924a93cace24507";
$Next_URL = $_GET["nexturl"];
if($Next_URL == ""){
$url = 'https://api.instagram.com/v1/tags/'.$tag.'/media/recent?client_id='.$client_id.'&count=24';
} else {
$url = $Next_URL;
}
$inst_stream = callInstagram($url);
$results = json_decode($inst_stream, true);
$maxid = $results['pagination']['next_max_id'];
$nexturl = $results['pagination']['next_url'];
//Now parse through the $results array to display your results...
foreach($results['data'] as $item){
$image_link = $item['images']['thumbnail']['url'];
$Profile_name = $item['user']['username'];
echo '<div style="display:block;float:left;">'.$Profile_name.' <br> <img src="'.$image_link.'" /></div>';
}
echo "<div style='display:block;width:100%;clear:both;'>MaxID: $maxid <br>NextURL: <a href='?nexturl=$nexturl'>Next images</a> <br>N: $Next_URL</div>";
使用此代码,我似乎能够获取一些图像,但当我单击 Next images 时无法显示下一个图像。
我正在尝试使用此处给出的min_tag_id 和max_tag_id 创建某种分页:https://instagram.com/developer/endpoints/
但我似乎这两个min_tag_id 和max_tag_id 不适合我,但为什么呢?
【问题讨论】:
标签: php pagination instagram