为什么 sinon 不替换实际的函数调用？

Question

我的功能是：

const PhoneNumber = require('awesome-phonenumber');
const twilio = require('twilio')(process.env.TWILIO_ACCOUNT_SID, process.env.TWILIO_AUTH_TOKEN);
const { twiml } = require('twilio');

exports.incoming = (requestBody) => {
  const MessagingResponse = twiml.MessagingResponse;
  const VoiceResponse = twiml.VoiceResponse;
  const pn = new PhoneNumber(requestBody.Body, 'US');
    return global.db.Conference.create({})
      .then((dbCreate) => {
        conferenceId = dbCreate.id;
        // Call originator
        return twilio.calls.create({
          to: requestBody.From,
          from: requestBody.To,
          url: `${process.env.API_URL}/calls/conference?id=${conferenceId}`
        });
      })

我的测试是：

const _ = require('lodash');
const sinon = require('sinon');
const twilio = require('twilio')(process.env.TWILIO_ACCOUNT_SID, process.env.TWILIO_AUTH_TOKEN);
const { twiml } = require('twilio');

const SmsController = require('../../../controllers/sms');
const twilioIncomingSmsReq = require('../../mocks/twilioIncomingSmsReq');

describe.only('Sms Controller', () => {
  let messagingResponseMessageStub;
  let conferenceCreateStub;

  beforeEach(() => {
    messagingResponseMessageStub = sinon.stub(twiml.MessagingResponse.prototype, 'message').returns(true);
    conferenceCreateStub = sinon.stub(global.db.Conference, 'create').resolves({ id: 1 });

    return;
  });

  afterEach(() => {
    messagingResponseMessageStub.restore();
    conferenceCreateStub.restore();
    return;
  });

  it.only('should call the originator and recipient', () => {
    let requestBody = _.clone(twilioIncomingSmsReq);
    console.log(twilio.calls);
    let twilioDialStub = sinon.stub(twilio.calls, 'create').resolves(true);
    console.log(twilio.calls);

    return SmsController.incoming(requestBody)
      .then(() => {
        sinon.assert.calledWith(twilioDialStub, {
          to: requestBody.From,
          from: requestBody.To,
          url: `${process.env.API_URL}/calls?id=1`
        });

        sinon.assert.calledWith(twilioDialStub, {
          to: '+number',
          from: requestBody.From,
          url: `${process.env.API_URL}/calls?id=1`
        });

        twilioDialStub.restore();

        return;
      });
  });
});

但在我的代码中，调用了实际的 twilion.calls.create 函数。不是存根。我做错了什么？

Answer 1

twilio 引用这些模块中的不同对象。 require('twilio') 是工厂函数。即使使用相同的参数require('twilio')(...) !== require('twilio')(...) 调用它，它也会创建一个新对象。

考虑导出twilio 实例，至少用于测试目的：

const twilio = require('twilio')(process.env.TWILIO_ACCOUNT_SID, 
...
exports.twilio = twilio;