Stata子字符串错误答案

【问题标题】：Stata substring errorStata子字符串错误
【发布时间】：2013-08-05 20:23:07
【问题描述】：

我正在尝试从供应商名称中删除某些子字符串。所以我放了一个宏并这样做：

 local item "BANKOFAMERICA"  " INC" " INCORPORATED" " SYS " " SYSTEMS" " PVT" " PRIVATE"    " LIMITED" " LTD" " LLC" " CORP" "LIMITED LIABILITY" "CORPORATION" " CORP " " COMPANY" " CO " " TECHNOLOGY" " TECH " " GLOBAL"
foreach v in `item' {
replace vendor = subinstr(vendor,"`v'","",.)
}

但是，这给了我一个引号太少的错误。我尝试在“v”周围复合“”，但没有奏效。知道我做错了什么/另一种方法来完成这个吗？

【问题讨论】：

这对你有用吗？

标签： stata

【解决方案1】：

您的嵌套引号给您带来了麻烦。您的代码可以通过在本地宏定义中添加一些 compound double quotes 并替换来修复：

local item `" "BANKOFAMERICA"  " INC" " INCORPORATED" " SYS " " SYSTEMS" " PVT" " PRIVATE"    " LIMITED" " LTD" " LLC" " CORP" "LIMITED LIABILITY" "CORPORATION" " CORP " " COMPANY" " CO " " TECHNOLOGY" " TECH " " GLOBAL" "'

foreach v of local item {
    replace vendor = subinstr(vendor,`"`v'"',"",.)
}

或者，您可以避免定义本地宏而只使用：

foreach v in "BANKOFAMERICA"  " INC" " INCORPORATED" " SYS " " SYSTEMS" " PVT" " PRIVATE"    " LIMITED" " LTD" " LLC" " CORP" "LIMITED LIABILITY" "CORPORATION" " CORP " " COMPANY" " CO " " TECHNOLOGY" " TECH " " GLOBAL" {
    replace vendor = subinstr(vendor,"`v'","",.)
}

这不像第一个变体那样清晰。

【讨论】：

【解决方案2】：

@Dimitriy V. Masterov 的回答很好。这只是说明了一个关键细节。

你可以通过去查看你的错误

. local item "BANKOFAMERICA"  " INC" " INCORPORATED" " SYS " " SYSTEMS" " PVT" " PRIVATE"    " LIMITED" " LTD" " LLC" " CORP" "LIMITED LIABILITY" "CORPORATION" " CORP " " COMPANY" " CO " " TECHNOLOGY" " TECH " " GLOBAL"

. mac li

发生的情况是第一个和最后一个" 被剥离为标记宏开始和结束的分隔符。您必须先使用复合双引号来阻止这种情况。就 Stata 而言，“”和“”是匹配字符（可以嵌套，尽管这里不需要）。

【讨论】：