【问题标题】:Conduit and Attoparsec: unexpected termination on parse errorConduit 和 Attoparsec:解析错误时意外终止
【发布时间】:2015-12-09 18:40:35
【问题描述】:

我正在尝试将我写了一段时间的日志文件解析器转换回管道,但我遇到了问题。我将简化解析器本身的细节,因为这与问题无关。我有一个如下所示的日志文件:

200 GET
404 POST
500 GET
FOO
301 PUT
302 GET
201 POST

所以解析代码非常简单:

data SimpleLogEntry = SimpleLogEntry {
      status :: Int
    , method :: String
} deriving (Show, Eq)


parseHTTPStatus :: Parser Int
parseHTTPStatus = validate <$> decimal
    where validate d = if (d >= 200 && d < 999) then d else 100


parseHTTPMethod :: Parser String
parseHTTPMethod =
        (stringCI "GET" *> return "Get")
    <|> (stringCI "POST" *> return "Post")
    <|> (stringCI "PUT" *> return "Put")
    <|> return "Unknown"


parseLogLine :: Parser SimpleLogEntry
parseLogLine = fmap SimpleLogEntry
        parseHTTPStatus
    <*> (space *> parseHTTPMethod)

到目前为止一切顺利。以下是我在管道中的实现方式:

import Prelude hiding (lines)

import Control.Applicative
import Control.Monad.IO.Class (liftIO)
import Control.Monad.Trans.Resource (runResourceT, ResourceT)
import Data.Attoparsec.ByteString.Char8
import qualified Data.ByteString as B
import qualified Data.ByteString.Char8 as B8
import Data.Conduit
import qualified Data.Conduit.Attoparsec as CA
import qualified Data.Conduit.Binary as CB
import qualified Data.Conduit.List as CL


logLines:: Source (ResourceT IO) B.ByteString
logLines = CB.sourceFile "~/test.log" $= CB.lines


parseEntry :: ConduitM B8.ByteString SimpleLogEntry (ResourceT IO) ()
parseEntry = CA.conduitParserEither parseLogLine =$= awaitForever go
    where
        go (Left err) = liftIO $ putStrLn ("Got an error: " ++ CA.errorMessage err)
        go (Right (_, logEntry)) = yield logEntry


sink :: Sink SimpleLogEntry (ResourceT IO) ()
sink = CL.mapM_ (\t -> liftIO $ putStrLn $ "Got a status: " ++ (show . status) t)


main :: IO ()
main = runResourceT $ logLines $= parseEntry $$ sink

运行 main 时,我得到以下输出:

Got a status: 200
Got a status: 404
Got a status: 500
Got an error: Failed reading: takeWhile1

我无法理解为什么管道会在此时终止,而不是像我想做的那样继续解析文件的下一行。阅读Data.Conduit.Attoparsec 的文档,这似乎正是为conduitParserEither 设计的用例。

更新

根据@Fabian,事实证明conduitParserEither 并不是我真正想要的。这是 parseEntry 的定义,可以满足我的要求:

parseEntry' :: ConduitM B8.ByteString SimpleLogEntry (ResourceT IO) ()
parseEntry' = (CL.map (parseOnly parseLogLine)) =$= awaitForever go
    where
        go (Left err) = liftIO $ putStrLn ("Got an error: " ++ err)
        go (Right logEntry) = yield logEntry

【问题讨论】:

    标签: haskell conduit attoparsec


    【解决方案1】:

    conduitParser(或conduitParserEither)也可以在一行中使用多个标记:例如,以下输入产生相同的结果:

    200 GET404 POST
    500 GET
    FOO
    301 PUT
    302 GET
    201 POST
    

    所以解析器不继续是有道理的,因为它不知道下一个标记将从哪里开始。

    【讨论】:

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