Java中的i ++和++ i [重复]

Question

    int i = 1;
    i = i++;
    int j = i++;
    int k = i + ++i * i++;
    System.out.println("i==" + i);
    System.out.println("j==" + j);
    System.out.println("k==" + k);

为什么k的结果是11？我是java的学习者。请帮助我并解释幕后发生的事情，或者如果可能的话，请给我一些关于在哪里可以找到相关学习资源的指示。

Answer 1

int i = 1; // i == 1
i = i++; // i is incremented, but the original value of i is assigned back to i, so i == 1
int j = i++; // i == 2
int k = i + ++i * i++; // k = 2 (the original value of i before this statement) + 
                       //     3 (the result of pre-incrementing i) * 
                       //     3 (the result of post-incrementing i is still 3) == 11
System.out.println("i==" + i);
System.out.println("j==" + j);
System.out.println("k==" + k);

请注意，2 + 3 * 3 被评估为 2 + (3 * 3)。