查找以 [重复] 开头的最新文件

Question

我希望通过共轭函数来查找以以下开头的最新文件：

$path = "/home/www/images/xml_cache"; 
$nom="images_album_6*.xml";

foreach (glob($path.'/'.$nom.'') as $filename) { }

和

  $latest_ctime = 0;
  $latest_filename = '';  
  $d = dir($path);
  while (false !== ($entry = $d->read( )))  {
    $filepath = "{$path}/{$entry}";
    // could do also other checks than just checking whether the entry is a file
    if (is_file($filepath) && filectime($filepath) > $latest_ctime) {
      $latest_ctime = filectime($filepath);
      $latest_filename = $entry;
    }
  }
}

但是怎么做呢？

提前谢谢你

Answer 1

假设你有PHP5，你可以使用RecursiveIterator类和getMTime函数：

$path = "/home/www/images/xml_cache"; 
$pattern = "/^images_album_6\S+.xml/i";
$latest_time = 0;
$latest_filename = '';
$iterator = new RecursiveIteratorIterator(new RecursiveDirectoryIterator($path), RecursiveIteratorIterator::CHILD_FIRST);
foreach ($iterator as $file) {
    if ($file->isFile() && preg_match($pattern,$file->getFilename())) {
        if ($file->getMTime() > $latest_time) {
            $latest_time = $file->getMTime();
            $latest_filename = $file->getPathname();
        }
    }
}
print("Latest file: ".$latest_filename.PHP_EOL);

这将递归检查您指定的路径并打印与您的文件名模式匹配的最新文件的完整路径。