【发布时间】:2013-06-19 10:10:10
【问题描述】:
我正在尝试编写一个简短的测试来测试我遇到的一些电子邮件问题。
我的测试邮件(删除了一些个人信息):
Received: from <address> (<ip>) by
<address> (<ip>) with Microsoft SMTP
Server (TLS) id <ip>; <time>
Received: from <address> (<ip>) by
<address> (<ip>) with mapi id
<ip>; <time>
From: <name> <<mail>>
To: <name> <<mail>>
Subject: =?iso-8859-1?Q?<subject>?=
Thread-Topic: =?iso-8859-1?Q?<subject>?=
Thread-Index: <index>==
Date: <time>
Message-ID: <<message-id>>
References: <<references-id>>
<<references-id>>
<<references-id>>
In-Reply-To: <<references-id>>
Accept-Language: sv-SE, en-US
Content-Language: sv-SE
X-MS-Exchange-Organization-AuthAs: Internal
X-MS-Exchange-Organization-AuthMechanism: 04
X-MS-Exchange-Organization-AuthSource: <<address>>
X-MS-Has-Attach:
X-MS-Exchange-Organization-SCL: -1
X-MS-Exchange-Inbox-Rules-Loop: <address>
X-MS-TNEF-Correlator:
Content-Type: text/html; charset="iso-8859-1"
Content-Transfer-Encoding: quoted-printable
MIME-Version: 1.0
<html>
<head>
<meta http-equiv=3D"Content-Type" content=3D"text/html; charset=3Diso-8859-=1">
</head>
<body>
text, nothing special a bit of css and some html code
</body>
</html>
我的测试代码:
Session s = Session.getDefaultInstance(new Properties());
mime = EmailTest.class.getResourceAsStream("/mailtests/parsehtmlmail1.mime");
MimeMessage msg = new MimeMessage(s, mime);
InputStream is = msg.getRawInputStream();
System.out.println(is.read());
if(msg.getContentType().toLowerCase().startsWith("text/html")){
if(msg.isMimeType("text/html")){
if(msg.getContent() instanceof String) {
System.out.println("Here");
System.out.println(msg.getContent().toString());
InputStream is2 = msg.getInputStream();
System.out.println(is2.read());
}
}
}
结果:
-1
Here
-1
所以我的问题是,无论我尝试什么,我都会以空内容字符串或空输入流结束。
那么我做错了什么?还是我不明白的东西?我的印象是我应该能够使用输入流,因为 mimetype 是 text/html。
这个错误可能与我的测试文件有关吗?我只复制了邮件并将其粘贴到我命名为“parsehtmlmail1.mime”的文件中。如果是这样,我怎么能使用 getContentType() 等?
【问题讨论】: