【发布时间】:2015-05-19 09:14:17
【问题描述】:
对于某些调试,我需要获取由 TVPDataCollection 类的方法 IEnumerator IEnumerable.GetEnumerator() 生成的 SqlDataRecord 列表
这段代码:
TVPDataCollection<AttributiDocumento> oAttributiDocumentoList = new TVPDataCollection<AttributiDocumento>();
AttributiDocumento doc1 = new AttributiDocumento();
AttributiDocumento doc2 = new AttributiDocumento();
oAttributiDocumentoList.Add(doc1);
oAttributiDocumentoList.Add(doc2);
var x = oAttributiDocumentoList.GetEnumerator();
x 是 AttributiDocumento 的列表,但我需要 SqlDataRecord 的列表,因为我想检查这些值。调用返回SqlDataRecord的GetEnumerator()方法是什么?
public class TVPDataCollection<T> : List<T>, IEnumerable<SqlDataRecord> where T : class
{
IEnumerator<SqlDataRecord> IEnumerable<SqlDataRecord>.GetEnumerator()
{
List<SqlMetaData> records = new List<SqlMetaData>();
var properties = typeof(T).GetProperties();
foreach (var prop in properties)
{
SqlType oSqlType = GetSqlType(prop);
if (oSqlType.UseSize)
records.Add(new SqlMetaData(prop.Name, oSqlType.SqlDbType, oSqlType.Size));
else
records.Add(new SqlMetaData(prop.Name, oSqlType.SqlDbType));
}
SqlDataRecord oSqlDataRecord = new SqlDataRecord(records.ToArray());
foreach (T data in this)
{
for (int i = 0; i < properties.Length; i++)
{
oSqlDataRecord.SetValue(i, properties[i].GetValue(data, null));
}
yield return oSqlDataRecord;
}
}
}
public class AttributiDocumento
{
public int IdProvPart { get; set; }
//uso stringa in quanto con data agigunge 2 ore del fuso orario
public DateTime Data { get; set; }
public int Articolo { get; set; }
public int ExArticolo { get; set; }
public int DocVer { get; set; }
[LenAttribute(255)]
public string Altro { get; set; }
public AttributiDocumento()
{
this.Data = new DateTime(1900, 1, 1);
this.Altro = string.Empty;
}
}
【问题讨论】:
标签: c#