C中的'For'循环无休止地循环[关闭]

Question

我知道以前有人问过这个问题，但我一直找不到可以应用于我的案例的答案。

我无法让这个 For 循环结束。我确定这很简单，谁能告诉我我做错了什么？

#include <stdio.h>
int main ()
{
  /* variable definition: */
  char StudentName[100];
  float ExamValue, Sum, Avg;
  int students, exams;
  int Total_Students;

    printf("Enter total number of students: \n");
    scanf("%d", &Total_Students);

   // Loop through x students
  for (students = Total_Students; students++;)
  {
     // reset Sum to 0
     Sum =0.0;  
     printf("Enter Student Name \n");
     scanf("%s", StudentName); 

     // Nested Loop for Exams
    for (exams=0; exams < 3; exams++)
    {
        printf ("Enter exam grade: \n");
        scanf("%f", &ExamValue);
        Sum += ExamValue;
    }   
    Avg = Sum/3.0;
    printf( "Average for %s is %f\n",StudentName,Avg);
  }
  return 0;
}

Answer 1

在预期循环 x 个学生的外部循环中，实际上是从 x 个学生开始，一直到无穷大。您应该从零开始，并以“学生总数”为界限。

Answer 2

此代码可以解决您的问题。 你应该这样设置条件，准确设置起点，终点

#include <stdio.h>
int main()
{
/* variable definition: */
char StudentName[100];
float ExamValue, Sum, Avg;
int students, exams;
int Total_Students;

printf("Enter total number of students: \n");
scanf_s("%d", &Total_Students);

// Loop through x students
// you should make condition like this, set the start, end point accurately
for ( students = Total_Students; students>0; students--)
{
    // reset Sum to 0
    Sum = 0.0;
    printf("Enter Student Name : \n");
    scanf_s("%s", StudentName,sizeof(StudentName));
    getchar();

    // Nested Loop for Exams
    for (exams = 0; exams < 3; exams++)
    {
        printf("Enter exam grade: \n");
        scanf_s("%f", &ExamValue);
        Sum += ExamValue;
    }
    Avg = Sum / 3.0;
    printf("Average for %s is %f\n", StudentName, Avg);
}
return 0;
}