【发布时间】:2016-07-12 23:57:01
【问题描述】:
作为学习 Haskell、Conduit 和 Monads 的练习,我想创建一个 告诉输入值并传递它的管道。
代码非常简单,但我遇到的编译错误对我来说仍然很神秘:
log =
await >>= \case
Nothing -> return ()
Just value -> do
tell [value]
yield value
runWriter $ CL.sourceList ["a", "b"] $= log $$ CL.consume
还有错误:
No instance for (MonadWriter [o0] m0) arising from a use of ‘tell’
The type variables ‘m0’, ‘o0’ are ambiguous
Relevant bindings include
value :: o0
(bound at /home/vagrant/workspace/dup/app/Main.hs:241:10)
logg :: ConduitM o0 o0 m0 ()
(bound at /home/vagrant/workspace/dup/app/Main.hs:238:1)
Note: there are several potential instances:
instance MonadWriter w m => MonadWriter w (ConduitM i o m)
-- Defined in ‘conduit-1.2.6.4:Data.Conduit.Internal.Conduit’
instance MonadWriter w m =>
MonadWriter
w (conduit-1.2.6.4:Data.Conduit.Internal.Pipe.Pipe l i o u m)
-- Defined in ‘conduit-1.2.6.4:Data.Conduit.Internal.Pipe’
instance [safe] MonadWriter w m =>
MonadWriter w (Control.Monad.Trans.Resource.Internal.ResourceT m)
-- Defined in ‘Control.Monad.Trans.Resource.Internal’
...plus 11 others
In a stmt of a 'do' block: tell [value]
In the expression:
do { tell [value];
yield value }
In a case alternative:
Just value
-> do { tell [value];
yield value }
【问题讨论】:
-
这种类型会帮我检查lpaste.net/169714 会不会是进口的问题?
-
请注意,您可能打算让
log管道在它命中的第一个项目之后继续。因为它只有一项可以通过。所以你应该递归循环,或者使用awaitForever之类的。