mysql - 查询以查找每天每小时累积的 SUM

Question

我正在尝试创建一个查询，该查询将累积全天 24 小时轮班的员工人数。因此，当用户从 2013 年 6 月 17 日 10:00:00 开始并结束 14:00:00 轮班时，我希望用户在 5 个单元格中“计数”

2013-06-17 10 : +1 here
2013-06-17 11 : +1 here
2013-06-17 12 : +1 here
2013-06-17 13 : +1 here
2013-06-17 14 : +1 here

这最终应该会为我提供 24 小时的范围，显示在特定时间有多少员工在工作。

我有 3 个我使用的表。

teamslots
---------
id
startdate
starttime
endtime

teamslot_schedule
-----------------
id
slotid (joins to is in teamslots)
userid

shifthours
----------
thehour

在轮班时间，我有 24 条记录 - 0 - 23 条记录，每小时需要一条。

然后我尝试在 HOUR(teamslots.starttime) 和 GROUP BY startdate,thehour 上离开，但没有真正的运气。

这是我的查询（当前返回 24 行的小时，空，空）

SELECT a.thehour,b.startdate,b.taken FROM shifthours a LEFT JOIN (SELECT startdate,starttime,endtime,count(DISTINCT b.id) as taken FROM teamslots a
LEFT JOIN teamslot_schedule b ON a.id=b.slotid) b ON a.thehour=HOUR(b.starttime)
GROUP BY b.startdate,a.thehour;

有人可以帮我吗？指出正确的方向吗？

Answer 1

简单的想法。想出相关日期的时间范围（假设这一天是查询提前知道的）并在开始时间和结束时间之间进行 JOIN。

像这样：-

SELECT DATE_ADD('2013/06/17', INTERVAL thehour HOUR), COUNT(teamslot_schedule.id)
FROM shifthours
LEFT OUTER JOIN teamslots
ON DATE_ADD('2013/06/17', INTERVAL thehour HOUR) BETWEEN starttime AND starttime AND endtime
LEFT OUTER JOIN teamslot_schedule
ON teamslots.id = teamslot_schedule.slotid
GROUP BY DATE_ADD('2013/06/17', INTERVAL thehour HOUR)

请注意，这不会直接奏效，因为我不确定您的开始时间/结束时间与开始日期的关系。

Answer 2

以下查询将包括无人工作时的几个小时的存储桶：

SELECT
    DATE_FORMAT(d.startdate + INTERVAL s.thehour HOUR, '%Y-%m-%d %H') AS date,
    COUNT(DISTINCT ts.userid) AS users
FROM
    shifthours s
JOIN
    (SELECT DISTINCT startdate FROM teamslots) d
LEFT JOIN
    teamslots t ON t.startdate = d.startdate AND
        s.thehour BETWEEN HOUR(t.starttime) AND HOUR(t.endtime)
LEFT JOIN
    teamslot_schedule ts ON ts.slotid = t.id
GROUP BY
    d.startdate,
    s.thehour
ORDER BY
    d.startdate + INTERVAL s.thehour HOUR;

有关工作示例，请参阅http://sqlfiddle.com/#!2/4a716/13

以下查询将仅包含有人工作时的行：

SELECT
    DATE_FORMAT(t.startdate + INTERVAL s.thehour HOUR, '%Y-%m-%d %H') AS date,
    COUNT(DISTINCT ts.userid) AS users
FROM
    shifthours s
INNER JOIN
    teamslots t ON s.thehour BETWEEN HOUR(t.starttime) AND HOUR(t.endtime)
LEFT JOIN
    teamslot_schedule ts ON ts.slotid = t.id
GROUP BY
    t.startdate,
    s.thehour
ORDER BY
    t.startdate + INTERVAL s.thehour HOUR;

有关工作示例，请参阅http://sqlfiddle.com/#!2/4a716/15