如果一个值多次出现，则从列表中删除两项（Python）

Question

Python: How to remove all duplicate items from a list

大家好

我有一个 (file,inode,image,hash)-tuples 列表。如果它们具有相同的哈希值，我需要删除这两个项目。我没有那么多的编程经验，所以也许对我必须看的东西的提示已经很有帮助了。 我已经在互联网上搜索过，但我唯一找到的是this。 到目前为止，我已经想出了这个（非常尴尬）的解决方案：

        hashlist = {}
        files_tobe_removed = []
        for (file, inode, image, hash) in self.files_for_json:
            hashlist[hash] = 0
        for (file, inode, image, hash) in self.files_for_json:
            hashlist[hash] +=1
        for (k,v) in hashlist.iteritems():
            if v == 2:
                files_tobe_removed.append(k)
        for (file,inode,image,hash) in self.files_for_json:
            if hash in files_tobe_removed:
                path = self.outDir + file
                os.remove(path)
                self.files_for_json.remove((file,inode,image,hash))

任何帮助将不胜感激。提前致谢

Answer 1

>>> from collections import Counter
>>> L=[1,2,3,4,5,6,7,8,9,1,2,3,4,5,6,1,2,3]
>>> [k for k,v in Counter(L).items() if v==1]
[7, 8, 9]

澄清一下：

hash_counter = Counter(x[3] for x in self.files_for_json)
for (file,inode,image,hash) in self.files_for_json:
    if hash_counter[hash]>1:
        # duplicated hash
        ...