使用私有 API 读取 WiFi RSSI 值

Question

我正在开发一些不需要在 App Store 上的东西，所以我对使用私有 API 来满足我的需求没有任何问题 我正在尝试使用 MobileWiFi. framework to read the RSSI value for the wireless network the phone is currently connected to. I've included thehttps://github.com/Cykey/ios-reversed-headers/tree/c613e45f3ee5ad9f85ec7d43906cf69ee812ec6a/MobileWiFi` 标头并使用桥接头将它们包含在我的 swift 项目中并编写如下代码。请原谅，我是新手。

import SystemConfiguration.CaptiveNetwork
typealias _WiFiManagerClientCreate = @convention(c) (CFAllocator, CInt) -> UnsafeRawPointer
typealias _WiFiManagerClientCopyDevices = @convention(c) (UnsafeRawPointer) -> CFArray
typealias _WiFiDeviceClientCopyProperty = @convention(c) (UnsafeRawPointer, CFString) -> CFPropertyList

if let libHandle = dlopen (Paths.ipConfiguration, RTLD_LAZY) {
        result = libHandle.debugDescription

        let _createManagerPtr = dlsym(libHandle, "WiFiManagerClientCreate")
        let _clientCopyDevicesPtr = dlsym(libHandle, "WiFiManagerClientCopyDevices")
        let _clientCopyPropertyPtr = dlsym(libHandle, "WiFiDeviceClientCopyProperty")

        if (_createManagerPtr != nil) && (_clientCopyDevicesPtr != nil) && (_clientCopyPropertyPtr != nil) {
            let _createManager = unsafeBitCast(_createManagerPtr, to: _WiFiManagerClientCreate.self)
            let _clientCopyDevices = unsafeBitCast(_clientCopyDevicesPtr, to: _WiFiManagerClientCopyDevices.self)
            let _clientCopyProperty = unsafeBitCast(_clientCopyPropertyPtr, to: _WiFiDeviceClientCopyProperty.self)

            let manager = _createManager(kCFAllocatorDefault, 0)
            let devices = _clientCopyDevices(manager)
            let client = CFArrayGetValueAtIndex(devices, 0)

            let data = _clientCopyProperty(client!, "RSSI" as CFString)
            let rssi = CFDictionaryGetValue(data as! CFDictionary, "RSSI_CTL_AGR")

            NSLog("RSSI: \(rssi)")
        }

        dlclose(libHandle)
    }

这会产生错误fatal error: unexpectedly found nil while unwrapping an Optional value which stems from trying to call _createManager

Answer 1

我最终使用了这个解决方法：

+ (int) wifiStrength {
UIApplication *app = [UIApplication sharedApplication];
NSArray *subviews = [[[app valueForKey:@"statusBar"] valueForKey:@"foregroundView"] subviews];
NSString *dataNetworkItemView = nil;

for (id subview in subviews) {
    if([subview isKindOfClass:[NSClassFromString(@"UIStatusBarDataNetworkItemView") class]]) {
        dataNetworkItemView = subview;
        break;
    }
}

return[[dataNetworkItemView valueForKey:@"wifiStrengthRaw"] intValue];
}

无需任何权利或越狱即可工作

Answer 2

由于 iPhone X 的状态栏与其他 iPhone 不同，因此获取 WiFi 信息的方式也不同。

这里是关于如何通过“undocumented properties”获取它的解决方法，这意味着 Apple 将来可能会在不通知我们的情况下更改这些属性。 如果 Apple 更改了未记录的属性，但我们没有相应地调整我们的代码，应用程序将会崩溃。所以我们必须在 Swift 中处理 NSException。

创建一个头文件，并将其添加到您的 Bridging-Header.h 中。 你可以找到文件here:https://gist.github.com/zhihuitang/6d3de0963d96a552d47721a598ca79c8

//
//  OCCatch.h
//
//

#ifndef OCCatch_h
#define OCCatch_h

// add the code below to your -Bridging-Header.h

/**
 #import "OCCatch.h"
 */

//   How to use it in Swift?
/**
 let exception = tryBlock {
        let statusBar = UIApplication.shared.value(forKey: "statusBar") as? UIView
        //......
    }
  if let exception = exception {  
    print("exception: \(exception)")
  }  
*/

#import <Foundation/Foundation.h>

NS_INLINE NSException * _Nullable tryBlock(void(^_Nonnull tryBlock)(void)) {
    @try {
        tryBlock();
    }
    @catch (NSException *exception) {
        return exception;
    }
    return nil;
}

#endif /* OCCatch_h */

在 iPhoneX 中，我们可以得到 WiFi 的 numberOfActiveBars，范围从 0 到 3。 在 iPhoneX 以外的其他 iPhone 上，我们可以获取 WiFi RSSI。

在iPhoneX上，请使用getWiFiNumberOfActiveBars()：

 private func getWiFiNumberOfActiveBars() -> Int? {
    let app = UIApplication.shared
    var numberOfActiveBars: Int?
    let exception = tryBlock {
        guard let containerBar = app.value(forKey: "statusBar") as? UIView else { return nil }
        guard let statusBarMorden = NSClassFromString("UIStatusBar_Modern"), containerBar .isKind(of: statusBarMorden), let statusBar = containerBar.value(forKey: "statusBar") as? UIView else { return nil }

        guard let foregroundView = statusBar.value(forKey: "foregroundView") as? UIView else { return nil }

        for view in foregroundView.subviews {
            for v in view.subviews {
                if let statusBarWifiSignalView = NSClassFromString("_UIStatusBarWifiSignalView"), v .isKind(of: statusBarWifiSignalView) {
                    if let val = v.value(forKey: "numberOfActiveBars") as? Int {
                        numberOfActiveBars = val
                        break
                    }
                }
            }
            if let _ = numberOfActiveBars {
                break
            }
        }
    }
    if let exception = exception {
        print("getWiFiNumberOfActiveBars exception: \(exception)")
    }

    return numberOfActiveBars
}

在 iPhoneX 以外的 iPhone 设备上，请使用getWiFiRSSI()：

private func getWiFiRSSI() -> Int? {
    let app = UIApplication.shared
    var rssi: Int?
    let exception = tryBlock {
        guard let statusBar = app.value(forKey: "statusBar") as? UIView else { return }
        if let statusBarMorden = NSClassFromString("UIStatusBar_Modern"), statusBar .isKind(of: statusBarMorden) { return }

        guard let foregroundView = statusBar.value(forKey: "foregroundView") as? UIView else { return  }

        for view in foregroundView.subviews {
            if let statusBarDataNetworkItemView = NSClassFromString("UIStatusBarDataNetworkItemView"), view .isKind(of: statusBarDataNetworkItemView) {
                if let val = view.value(forKey: "wifiStrengthRaw") as? Int {
                    rssi = val
                    break
                }
            }
        }
    }
    if let exception = exception {
        print("getWiFiRSSI exception: \(exception)")
    }
    return rssi
}

到目前为止，我还没有找到在 iPhoneX 上获取 WiFi RSSI 的方法。如果你们知道怎么做，也请告诉我。谢谢。

这是 Github 中的demo project

Answer 3

我认为最新版本的 iOS 是不可能的。最多只能到 iOS4。

Answer 4

苹果不喜欢这种做法，威胁app review rejection