【发布时间】:2014-07-08 10:33:04
【问题描述】:
我正在处理一个简单的联系表格,但是当电子邮件通过这些字段时是空的。表单发送良好,但没有获得任何值。我的表单 HTML 如下所示。
<form id="main-contact-form" class="contact-form" name="contact-form" method="post" action="sendemail.php">
<input type="text" name="namefirst" id="namefirst" class="input-block-level" required="required" placeholder="Your First Name">
<input type="text" name="namefirst" id="namefirst" class="input-block-level" required="required" placeholder="Your First Name">
<input type="text" name="email" id="email" class="input-block-level" required="required" placeholder="Your email address">
<textarea name="message" id="message" required="required" class="input-block-level" rows="8"></textarea>
<button type="submit" class="btn btn-primary btn-large pull-right">Send Message</button>
PHP 方面如下
header('Content-type: application/json');
$status = array(
'type'=>'success',
'message'=>'Email sent!'
);
$nameFirst = $_POST['namefirst'];
$nameLast = $_POST['namelast'];
$email = $_POST['email'];
$message = $_POST['message'];
$subject = $message;
$email_from = $email;
$email_to = 'jdwman14@gmail.com';
$body = 'Name: ' . $nameFirst .' '. $nameLast. "\n\n" . 'Email: ' . $email . "\n\n" . 'Subject: ' . $subject . "\n\n" . 'Message: ' . $message;
$success = @mail($email_to, $subject, $body, 'From: <'.$email_from.'>');
echo json_encode($status);
die;
当电子邮件通过时,它具有这种格式,但没有任何变量。
姓名:
电子邮件:
主题:
消息:
【问题讨论】:
-
输入
print_r($_POST)看看你在数组中得到了什么。 -
除此之外:您有两次相同的名称 (
namefirst) - 请务必检查count($_POST) > 0和值是否已设置(提示:isset())。
标签: php forms twitter-bootstrap post