【问题标题】:Can I call a virtual function that is overridden from main()?我可以调用被 main() 覆盖的虚函数吗?
【发布时间】:2019-12-14 19:47:39
【问题描述】:

这个我知道


// C++ program for function overriding 

#include <bits/stdc++.h> 
using namespace std; 

class base 
{ 
public: 
    virtual void print () 
    { cout<< "print base class" <<endl; } 

    void show () 
    { cout<< "show base class" <<endl; } 
}; 

class derived:public base 
{ 
public: 
    void print () //print () is already virtual function in derived class, we could also declared as virtual void print () explicitly 
    { cout<< "print derived class" <<endl; } 

    void show () 
    { cout<< "show derived class" <<endl; } 
}; 

//main function 
int main()  
{ 
    base *bptr; 
    derived d; 
    bptr = &d; 

    //virtual function, binded at runtime (Runtime polymorphism) 
    bptr->print();  

    // Non-virtual function, binded at compile time 
    bptr->show();  

    return 0; 
} 

我可以打印出来

print derived class
show base class
show derived class

我可以打印吗

print base class

使用派生类的对象d 只更改main() 而不创建另一个对象?如果是怎么办?

【问题讨论】:

    标签: c++ polymorphism virtual-functions


    【解决方案1】:

    我可以用派生类的对象d打印打印基类,只需更改main()

    是的,你可以。您必须在调用中显式使用基类。

    bptr->base::print();  
    

    您也可以直接使用d

    d.base::print();  
    

    【讨论】:

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