我想从 with 的值中为函数提供参数

Question

WITH
EmpDetails(EmpCode)
AS
(
 SELECT EmpCode 
 FROM Employee.tblEmp_Demographics 
 WHERE RecordStatus='present' 
)  

    select *,ROW_NUMBER() OVER (PARTITION BY EmpCode ORDER BY DateTaken DESC) AS RowNum,    
    (select GradeName From Master.GradeMaster where GradeCode=Grade And Deleted=0) As Grade,    
    SUM(Amount) OVER(PARTITION BY Grade) AS EmpAmount,
    SUM(DependentAmount) OVER(PARTITION BY Grade) As DepAmount,
    0 As CheckNo 
    from [dbo].[SELECT_AIRTICKET_DETAILS_BY_DATE](EmpDetails.EmpCode,getdate(),1) WHERE YEAR(DateTaken)=year(getdate())

但我得到一个错误

Msg 4104，Level 16，State 1，Line 11 无法绑定多部分标识符“EmpDetails.EmpCode”。

Answer 1

我认为问题是您将列 EmpDetails.EmpCode 名称传递给表值函数而不是单个值的结果。你可以试试这个：

DECLARE @EmpCode nvarchar(100);

SELECT TOP 1
       @EmpCode = EmpCode 
  FROM Employee.tblEmp_Demographics
 WHERE RecordStatus='present';

select *,ROW_NUMBER() OVER (PARTITION BY EmpCode ORDER BY DateTaken DESC) AS RowNum,    
(select GradeName From Master.GradeMaster where GradeCode=Grade And Deleted=0) As Grade,    
SUM(Amount) OVER(PARTITION BY Grade) AS EmpAmount,
SUM(DependentAmount) OVER(PARTITION BY Grade) As DepAmount,
0 As CheckNo 
from [dbo].[SELECT_AIRTICKET_DETAILS_BY_DATE](@EmpCode,getdate(),1) WHERE YEAR(DateTaken)=year(getdate());

如果您想要来自 Employee.tblEmp_Demographics 表的多个值的结果，您可以遍历每个值（可能不是最好的），或者修改您的表值函数以返回包含所有 EmpCode 值的结果集，然后添加一个WHERE 子句根据需要过滤数据。

---

编辑

可能是这样的——注意修改后的函数返回所有 EmpCodes 并且少了一个参数：

select *,ROW_NUMBER() OVER (PARTITION BY EmpCode ORDER BY DateTaken DESC) AS RowNum,    
(select GradeName From Master.GradeMaster where GradeCode=Grade And Deleted=0) As Grade,    
SUM(Amount) OVER(PARTITION BY Grade) AS EmpAmount,
SUM(DependentAmount) OVER(PARTITION BY Grade) As DepAmount,
0 As CheckNo 
  FROM [dbo].[SELECT_AIRTICKET_DETAILS_BY_DATE](getdate(),1) AS [Tickets]
 INNER JOIN Employee.tblEmp_Demographics
         ON tblEmp_Demographics.EmpCode = [Tickets].EmpCode
        AND tblEmp_Demographics.RecordStatus = 'present'
 WHERE YEAR(DateTaken) = year(getdate());

使用此解决方案，该函数返回所有 EmpCode，但我们通过在 Employee.tblEmp_Demographics 表上执行 INNER JOIN 过滤掉不必要的。