【发布时间】:2010-11-10 05:19:17
【问题描述】:
我正在使用 UIImagepickerController 从相机拍照..我通过使用 cameraoverlayview 属性在相机视图上使用我自己的视图...当用户单击自定义视图中的按钮时,我想从相机拍照...我正在使用以下代码
- (void)viewDidLoad {
imagePickerController = [[UIImagePickerController alloc] init];
imagePickerController.sourceType = UIImagePickerControllerSourceTypeCamera;
[self presentModalViewController:imagePickerController animated:YES];
imagePickerController.showsCameraControls=NO;
imagePickerController.cameraOverlayView = self.customView;
}
- (IBAction) takePicture
{
[imagePickerController takePicture];
}
- (void)imagePickerController:(UIImagePickerController *)picker didFinishPickingMediaWithInfo:(NSDictionary *)info
{
NSString *mediaType = [info objectForKey:UIImagePickerControllerMediaType];
imageView.image = [info objectForKey:@"UIImagePickerControllerOriginalImage"];
[picker dismissModalViewControllerAnimated:YES];
}
- (void)imagePickerControllerDidCancel:(UIImagePickerController *)picker
{
[self dismissModalViewControllerAnimated:YES];
}
但是当我运行这段代码时它给了我错误
错误:FigCreateCGImageFromJPEG 返回 -12905。输入(空)为 773625 字节。
我还收到内存使用级别 2 和级别 1 的警告
并且 imageView 中没有显示图像.. 谁能帮助我我可能做错了什么? 顺便说一句,我正在使用安装了 iOS4.1 的 iPhone 3G
【问题讨论】:
-
不确定,但请查看 UIImage 与 UIImageView。我怀疑这可能与您的
[info objectforKey: ... ]通话有关。 -
实际上 didFinishPickingMediaWithInfo 甚至没有被调用..我已经包含了它的委托
标签: iphone ios4 uiimagepickercontroller