如何在 Objective-C 中获取字符数组的 NSString 等效项？

Question

更具体地说，我在代码中放置了一个断点 NSString *signStr = [NSString stringWithCString:text encoding:NSASCIIStringEncoding]; 我用secret= @"12345678901234567890" 和movingFactor = 1 调用函数 我注意到在断点处，signStr 是一个空字符串， 代码中还有其他明显的错误吗？ 谢谢

-(NSString*) generateOTP:(NSString*) secret with:(uint64_t) movingFactor
{
    NSString* result;

    const int DIGITS = 6;
    const int SIX_DIGITS = 1000000;

    char text[8];
    for (int i = 7; i >= 0; i--) {
        text[i] = movingFactor & 0xff;
        movingFactor >>= 8;
    }

    NSString *signStr = [NSString stringWithCString:text encoding:NSASCIIStringEncoding];

    NSString* hash = [self sha1UseKey:secret toSign:signStr];

    int offset = [hash characterAtIndex:[hash length] - 1] & 0xf;

    int binary = (([hash characterAtIndex:offset] & 0x7f) << 24) |
        (([hash characterAtIndex:offset+1] & 0xff) << 16) |
        (([hash characterAtIndex:offset+2] & 0xff) << 8) | ([hash characterAtIndex:offset+3] & 0xff);

    int otp = binary % SIX_DIGITS;

    result = [NSString stringWithFormat:@"%d", otp];

    NSString* zero = @"0";
    while ([result length] < DIGITS) {
        result = [zero stringByAppendingString:result];
    }
    return result;

}

Answer 1

要成为“C 字符串”，它必须以零结尾 ('\0')。如果movingFactor 为 1，那么最后一个字符将为0x01，并且第一个（以及每隔一个字节）由于移位而为零。这使得 first 字符为零，这使得字符串“空”。