检查两个循环是否返回一个值

Question

我想检查两个 for 循环是否返回匹配项，如果它们什么也没发生，但如果它们不执行，我希望打印一条消息，说明“找不到匹配项”之类的信息。像这样的：

if (loop1 == 0 && loop2 == 0) {
    NSLog(@"A match could not be found, please check your spelling");
};

因此，我的问题是，如何描述循环以便检查它们给出的值？

这是循环：

    for (SMADoc *aSearch in docs) {
        if ([search isEqualToString:[aSearch leadAuthour]]) {
            //Open the file that is represented by UrlToDoc for that specific object
            [[NSWorkspace sharedWorkspace] openFile:[aSearch urlToDoc]];
        }
    }
} else {
    //The string starts with a number and should be converted to an int and then the array of the numbers should be searched through
    int number = atoi(searchC);
    NSNumber *sNumber = [NSNumber numberWithInt:number];

    for (SMADoc *nSearch in docs) {
        if ([sNumber isEqualToNumber:[nSearch docNumber]]) {
            [[NSWorkspace sharedWorkspace] openFile:[nSearch urlToDoc]];
        }
    }

}

提前致谢！

Answer 1

由于您的自定义类符合 KVC，您可以使用 NSPredicate 同时执行检查，而无需任何循环。

表达式的意思是：如果docs包含一个docNumber是number或leadAuthour是search的对象，则跳过错误信息

  NSPredicate *predicate = [NSPredicate predicateWithFormat:@"docNumber == %i || leadAuthour == %@", number, search];
  if [[docs filteredArrayUsingPredicate:predicate] count] == 0 {
      NSLog(@"A match could not be found, please check your spelling");
  }

Answer 2

我解决了！我首先声明两个整数，每个循环一个，然后检查每次迭代是否找不到匹配项，即：

![search isEqualToString:[aSearch leadAuthour]]

如果这是真的，int 加一。然后，遍历数组后，如果int等于数组中的对象数，我就知道没有对象匹配，我可以打印出“找不到匹配项，请检查你的拼写” “-信息。这是它在代码中的样子：

int i = 0;
int j = 0;    

for (SMADoc *aSearch in docs) {
    if ([search isEqualToString:[aSearch leadAuthour]]) {
        //Open the file that is represented by UrlToDoc for that specific object
        [[NSWorkspace sharedWorkspace] openFile:[aSearch urlToDoc]];
    }
  if(![search isEqualToString:[aSearch leadAuthour]]){
    i++;
}
    if(i == [docs count]) {
  NSLog(@"A match could not be found, please check your spelling");
}
  }
} else {
//The string starts with a number and should be converted to an int and then the array of the numbers should be searched through
int number = atoi(searchC);
NSNumber *sNumber = [NSNumber numberWithInt:number];

for (SMADoc *nSearch in docs) {
    if ([sNumber isEqualToNumber:[nSearch docNumber]]) {
        [[NSWorkspace sharedWorkspace] openFile:[nSearch urlToDoc]];
    }
if(![search isEqualToString:[aSearch docNumber]]){
j++;
  }
if(j == [docs count]) {
  NSLog(@"A match could not be found, please check your spelling");
    }

}

我不知道它是否可以回答您自己的问题，但我这样做的目的是为可能提出相同问题的人提供答案。