【发布时间】:2020-08-06 11:45:42
【问题描述】:
我在 Postgres 中有一个包含以下列的表格:
col1
The study was terminated early by the sponsor on 13 January 2014 due to a decision to modify the drug development plan.
Due to positive preliminary results from other palifermin studies.
Asset terminated by PIB
Inconsistent training status of sniffer dogs
This study was terminated early due to poor recruitment
The study was terminated due to lack of recruitment.
The scientific director decided to terminate: low priority study with slow accrual
See Termination Reason in Detailed Description.
Investigator moved to new institution
This study was terminated for administrative reasons
The app was not completed in time to conduct a clinical trial on it within the funding grant's award period
字符串中有前导和后置空格,中间有 '\n' 或 '\t'。我尝试了以下查询,但似乎没有任何结果。
select btrim(col1, '\s') from table;
update table
SET col1 = upper(substring(REGEXP_REPLACE(col1, '(\s+)', '') from 1 for 1)) || lower(substring(REGEXP_REPLACE(why_stopped, '(\s+)', '') from 2));
update table
set col1= regexp_replace(col1, E'[\\n\\r\\f\\u000B\\u0085\\u2028\\u2029]+', ' ', 'g' );
select distinct replace( replace( replace( col1, E'\n', '\n' ), E'\t', '\t' ), E'\r', '\r' )
from table;
这里的任何建议都会很有帮助。
【问题讨论】:
标签: postgresql trim regexp-replace