【问题标题】:How to remove '\t', '\n' or extra spaces from a string in Postgres?如何从 Postgres 中的字符串中删除 '\t'、'\n' 或多余的空格?
【发布时间】:2020-08-06 11:45:42
【问题描述】:

我在 Postgres 中有一个包含以下列的表格:

col1
     The study was terminated early by the sponsor on 13 January 2014 due to a decision to modify     the drug development plan.   
     Due to positive preliminary results from other palifermin studies.   
     Asset terminated by PIB   
     Inconsistent training status of sniffer dogs   
     This study was terminated early due to poor recruitment   
     The study was terminated due to lack of recruitment.   
     The scientific director decided to terminate: low priority study with slow accrual   
     See Termination Reason in Detailed Description.   
     Investigator moved to new institution   
     This study was terminated for administrative reasons   
     The app was not completed in time to conduct a clinical trial on it within the funding grant's     award period 

字符串中有前导和后置空格,中间有 '\n' 或 '\t'。我尝试了以下查询,但似乎没有任何结果。

select btrim(col1, '\s') from table;

update table
SET col1 = upper(substring(REGEXP_REPLACE(col1, '(\s+)', '') from 1 for 1)) || lower(substring(REGEXP_REPLACE(why_stopped, '(\s+)', '') from 2));

update table
set col1= regexp_replace(col1, E'[\\n\\r\\f\\u000B\\u0085\\u2028\\u2029]+', ' ', 'g' );

select distinct replace( replace( replace( col1, E'\n', '\n' ), E'\t', '\t' ), E'\r', '\r' )
from table;

这里的任何建议都会很有帮助。

【问题讨论】:

    标签: postgresql trim regexp-replace


    【解决方案1】:

    要在字符串文字中使用反斜杠转义,您必须在它们前面加上 E;见the documentation

    所以试试

    btrim(col1, E' \t\n')
    

    【讨论】:

      【解决方案2】:

      你可以使用 trim() 函数SQL String Functions and Operators

      TRIM([LEADING | TRAILING | BOTH] [characters] FROM string)
      

      你可以在这里找到例子:

      postgresql-trim-function trim function

      【讨论】:

        【解决方案3】:

        我通过以下方式解决了问题:

        regexp_replace(why_stopped, '\s{2,}', ' ', 'g')

        【讨论】:

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