【发布时间】:2021-04-08 12:04:37
【问题描述】:
我用的是 swift run gradlew build,但是卡在 Start Daemom 上。
#!/usr/bin/swift sh
import Foundation
func shell(_ command: String) -> Void {
let task = Process()
task.standardOutput = FileHandle.standardOutput
task.standardError = FileHandle.standardError
task.standardInput = FileHandle.standardInput
task.arguments = ["-c", command]
task.launchPath = "/bin/sh"
task.currentDirectoryPath = "/Users/MyProjectPath"
task.launch()
task.waitUntilExit()
assert(task.terminationStatus == 0, "\(command)")
}
shell("./gradlew --debug --info :app:assembleRelease")
输出:
08:52:39.590 [DEBUG] [org.gradle.process.internal.DefaultExecHandle] Changing state to: STARTING
08:52:39.591 [DEBUG] [org.gradle.process.internal.DefaultExecHandle] Waiting until process started: Gradle build daemon.
08:52:39.601 [DEBUG] [org.gradle.process.internal.DefaultExecHandle] Changing state to: STARTED
08:52:39.602 [INFO] [org.gradle.process.internal.DefaultExecHandle] Successfully started process 'Gradle build daemon'
08:52:39.602 [DEBUG] [org.gradle.launcher.daemon.client.DefaultDaemonStarter] Gradle daemon process is starting. Waiting for the daemon to detach...
08:52:39.602 [DEBUG] [org.gradle.process.internal.ExecHandleRunner] waiting until streams are handled...
08:52:39.604 [DEBUG] [org.gradle.launcher.daemon.bootstrap.DaemonOutputConsumer] Starting consuming the daemon process output.
> Starting Daemon
它启动成功守护进程并等待守护进程输出,由于某种原因没有得到守护进程的输出。
【问题讨论】:
-
这是一个 Swift 脚本吗?因为如果是这种情况,那么脚本首先完成的异步就存在问题。您需要在末尾添加一个“无限循环”。
-
task.waitUntilExit()将等待退出 -
问题是脚本会提前结束。我知道,我玩过 Swift Script。
-
将其转换为 Swift 脚本使用 github.com/mxcl/swift-sh。出于某种原因,在 swift 脚本中,gradle 是等待启动一个恶魔。
-
如果你测试 curl stackoverflow.com vs ls 命令,它有效吗?