如何将 Http URL Connection 请求转换为 Volley 请求？答案

【问题标题】：How to convert HttpURL Connection request with to Volly request ??如何将 Http URL Connection 请求转换为 Volley 请求？
【发布时间】：2015-11-25 11:34:29
【问题描述】：

这是我的 HttpURLConnection 请求，它工作正常。我正在发送带有请求的 json 字符串现在我必须将此请求转换为 volley

  String jsonStr =    {"email":"test@gmail.com","full_name":"vghjj",
                   "locations":[],"mobile_no":"XXXXXXXXX",
                   "super_sectors":    [],"unique_device_id":"XXXXXXX","utm_params":"No Utm Params"}"


try {
        HttpURLConnection urlConnection = getHttpConnection(jsonStr, url, oauth, REQUEST_TYPE.POST.getType());

        if (urlConnection != null) {
            if (urlConnection.getResponseCode() == HttpURLConnection.HTTP_OK) {
                result = convertInputStreamToString(urlConnection.getInputStream());
            } 
        }
    } catch (Exception e) {
        return null;
    } 

private static HttpURLConnection getHttpConnection(String jsonStr , String strUrl, Oauth oauth, String type) {
    URL url = null;
    HttpURLConnection urlConnection = null;

    try {
        url = new URL(strUrl);
        /* */
        if (GlobalVariables.DEVELOPING)
            Log.v(TAG, url.toString());

        urlConnection = (HttpURLConnection) url.openConnection();
        urlConnection.setRequestMethod(type);
        urlConnection.setConnectTimeout(GlobalVariables.applyInternetConnectionTimeOut);
        urlConnection.setReadTimeout(GlobalVariables.applyInternetSocketTimeOut);
        urlConnection.setRequestProperty("Accept", "application/json");
        urlConnection.setRequestProperty("Content-type", "application/json");
        urlConnection.setRequestProperty("Authorization", oauth.getToken_type() + " " + oauth.getAccess_token());

        OutputStream os = urlConnection.getOutputStream();
        os.write(jsonStr.getBytes());
        os.flush();
        os.close();

        return urlConnection;
    } catch (MalformedURLException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    }
    return null;
}

我已经为同一个请求在 volley 中编写了这段代码

    StringRequest= new StringRequest(Request.Method.POST, url,
            new Response.Listener<String>() {
                @Override
                public void onResponse(String response) {

                  // Successfull Stuff
                }
            },
            new Response.ErrorListener() {
                @Override
                public void onErrorResponse(VolleyError error) {

                  Log.d(TAG, "onErrorResponse: " + error.toString());

                }
            }
    ) {

        @Override
        protected Map<String, String> getParams() {
            Map<String, String> params = new HashMap<String, String>();
            params.put("allValue", jsonStr);
            return params;
        }

        @Override
        public Map<String, String> getHeaders() throws AuthFailureError {
            Map<String, String> params = new HashMap<String, String>();
            params.put("Content-Type", "application/json");
            params.put("Accept", "application/json");
            params.put("Authorization", oauth.getToken_type() + " " + oauth.getAccess_token());
            return params;
        }
    };

    /*Generate Queue to line up apply request*/
    RequestQueue requestQueue =  VollySingleton.getsInstance().getmRequestQueue();
    requestQueue.add(stringRequest);

所以我的具体问题是 jsonStr 在 Volley 请求中去哪里 使用字符串请求它给出 400 错误（错误请求）使用 JSONObject 请求它给出 500 错误

在 Http URL Connection 中，一切正常，jsonStr 正在传入

OutputStream os = urlConnection.getOutputStream();
          os.write(jsonStr.getBytes());
        os.flush();
        os.close();

【问题讨论】：

如果您尝试从某个服务器获取JSON 数据，请使用JsonObjectRequest。接下来，您正在使用的代码不适用于硬编码的 JSON 字符串。您的代码正在尝试通过您提到的 URL 从服务器中提取 JSON 数据。查看本教程，您将了解volley 的工作原理。 (code.tutsplus.com/tutorials/…)
我阅读了文档，但从未发现任何关于 jsonStr 的请求，在 HttpURLConnection 中，它们是 OutputStream 的选项，我问过的那个选项或 volley 中的类似选项在哪里。
public void onResponse(String response){...} - response 与您的 jsonStr 相似。

标签： android android-volley httpurlconnection

【解决方案1】：

这就是我解决问题的方法在事件 HttpClient 请求中使用的 StringEntity 的创建对象

 StringEntity entity = new StringEntity(JsonStr);

然后重写方法

 @Override
        public String getBodyContentType() {
            return entity.getContentType().getValue();
        }

        @Override
        public byte[] getBody() {
            ByteArrayOutputStream outputStream = new ByteArrayOutputStream();
            try {
                entity.writeTo(outputStream);
            } catch (IOException e) {
                VolleyLog.e("IOException @ " + getClass().getSimpleName());
            }
            return outputStream.toByteArray();
        }

所以完整的答案将是

StringRequest= new StringRequest(Request.Method.POST, url,
        new Response.Listener<String>() {
            @Override
            public void onResponse(String response) {

              // Successfull Stuff
            }
        },
        new Response.ErrorListener() {
            @Override
            public void onErrorResponse(VolleyError error) {

              Log.d(TAG, "onErrorResponse: " + error.toString());

            }
        }
) {

     @Override
        public String getBodyContentType() {
            return entity.getContentType().getValue();
        }

        @Override
        public byte[] getBody() {
            ByteArrayOutputStream outputStream = new ByteArrayOutputStream();
            try {
                entity.writeTo(outputStream);
            } catch (IOException e) {
                VolleyLog.e("IOException @ " + getClass().getSimpleName());
            }
            return outputStream.toByteArray();
        }


    @Override
    public Map<String, String> getHeaders() throws AuthFailureError {
        Map<String, String> params = new HashMap<String, String>();
        params.put("Content-Type", "application/json");
        params.put("Accept", "application/json");
        params.put("Authorization", oauth.getToken_type() + " " + oauth.getAccess_token());
        return params;
    }
};

/*Generate Queue to line up apply request*/
RequestQueue requestQueue =  VollySingleton.getsInstance().getmRequestQueue();
requestQueue.add(stringRequest);

【讨论】：