只有满足条件，Regex 才能捕获某个字符串？

Question

我有这组数据：

• EndDate":"2024-10-24","Employee":"000A0001","Submitted":"N"
• EndDate":"2023-10-18","Employee":"000A0001","Submitted":"P"
• EndDate":"2021-01-02","Employee":"000A0001","Submitted":"J"
• EndDate":"2022-10-11","Employee":"000A0001","Submitted":"M"
• EndDate":"2020-09-18","Employee":"000A0001","Submitted":"N"

我只想捕获提交值为 N 或 M 的 EndDate。

捕获的 EndDate 应该是：

• 2024-10-24
• 2022-10-11
• 2020-09-18

Answer 1

是的，您可以使用正则表达式积极前瞻来做到这一点：

\d{4}-\d{2}-\d{2}(?=.+"Submitted":"[NM]")

更多详情：Regex lookahead, lookbehind and atomic groups

Answer 2

捕获日期并使用前瞻：

"EndDate":"([^"]+)"(?=.*"Submitted":"[NM]")

您的结束日期在比赛的第 1 组。

注意：我在正则表达式的开头添加了 '"'，假设您不小心从看起来是 json 的示例中省略了它。