【发布时间】:2021-11-17 20:58:45
【问题描述】:
我想使用update().set() 移动记录的日期时间。当我尝试given example in the jOOQ docs for using a subselect 时,我发现我需要转换为Row2 类型,因为我想设置两个变量。有了这个,查询以一种不寻常的方式构建(或者至少不符合我对 jOOQ 文档中示例的查询的期望):
public static void moveEventStart(final LocalDate previousEventStart, final LocalDate newEventStart) {
final Days changeInterval = Days.daysBetween(previousEventStart, newEventStart);
ActivityTbl a = ACTIVITY.as("a");
ActivityTbl a2 = ACTIVITY.as("a2")
jooq()
.update(a)
.set(
(Row2) row(a.START, a.END),
select(
models.Jooq.dateAdd(a2.START, changeInterval.getDays(), DatePart.DAY),
models.Jooq.dateAdd(a2.END, changeInterval.getDays(), DatePart.DAY))
.from(a2)
.where(...))
.where(...)
.execute();
}
dateAdd 函数是这样构建的:
public static Field<Date> dateAdd(TableField<?, LocalDateTime> field, int interval, DatePart datePart) {
String unit;
switch (datePart) {
case YEAR:
unit = "YEAR";
break;
case MONTH:
unit = "MONTH";
break;
case DAY:
unit = "DAY";
break;
case HOUR:
unit = "HOUR";
break;
case MINUTE:
unit = "MINUTE";
break;
case SECOND:
unit = "SECOND";
break;
default:
unit = "";
}
return DSL.field(
"DATE_ADD({0}, INTERVAL {1} " + unit + ")", SQLDataType.DATE, field, DSL.inline(interval));
}
生产:
update `Activity` as `a`
set(`start`, `end`) = (
select * from (
select
DATE_ADD(`a2`.`start`, INTERVAL 1 DAY),
DATE_ADD(`a2`.`end`, INTERVAL 1 DAY)
from `Activity` as `a2`
where (...) as `t`
)
where (...)
为什么jOOQ 在已经给出的select 之上构建select?以及如何使这项工作,以便它根据给定的选择设置多个值?
【问题讨论】: