在 Python 中将字母转换为电话号码的数字

Question

我正在尝试编写一个程序，提示用户输入电话号码作为字符串。输入可以包含字母，程序将字母（无论是大写还是小写）转换为数字，而其他所有字符保持不变。这是我目前所拥有的：

def getNumber(uppercaseLetter):
    if uppercaseLetter == 'A':
        number = 2
    elif uppercaseLetter == 'B':
        number = 2
    elif uppercaseLetter == 'C':
        number = 2
    elif uppercaseLetter == 'D':
        number = 3
    elif uppercaseLetter == 'E':
        number = 3
    elif uppercaseLetter == 'F':
        number = 3
    elif uppercaseLetter == 'G':
        number = 4
    elif uppercaseLetter == 'H':
        number = 4
    elif uppercaseLetter == 'I':
        number = 4
    elif uppercaseLetter == 'J':
        number = 5
    elif uppercaseLetter == 'K':
        number = 5
    elif uppercaseLetter == 'L':
        number = 5
    elif uppercaseLetter == 'M':
        number = 6
    elif uppercaseLetter == 'N':
        number = 6
    elif uppercaseLetter == 'O':
        number = 6
    elif uppercaseLetter == 'P':
        number = 7
    elif uppercaseLetter == 'Q':
        number = 7
    elif uppercaseLetter == 'R':
        number = 7
    elif uppercaseLetter == 'S':
        number = 7
    elif uppercaseLetter == 'T':
        number = 8
    elif uppercaseLetter == 'U':
        number = 8
    elif uppercaseLetter == 'V':
        number = 8
    elif uppercaseLetter == 'W':
        number = 9
    elif uppercaseLetter == 'X':
        number = 9
    elif uppercaseLetter == 'Y':
        number = 9
    elif uppercaseLetter == 'Z':
        number = 9
    return number

def translateNumber():
    phoneNumber = str(input("Enter a string: "))
    for char in phoneNumber:
        if char in    ['A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z']:
        getNumber(char)
        return char
        else:
            return char
        print(phoneNumber)

由于某种原因，我无法让它工作，而且我不确定问题出在哪里。有人可以帮我解决问题吗？谢谢！

Answer 1

没有解释您的代码（Chrisitan 已经完成）。这只是一种方法：

>>> char_numbers = [('abc',2), ('def',3), ('ghi',4), ('jkl',5), ('mno',6), ('pqrs',7), ('tuv',8), ('wxyz',9)]
>>> char_num_map = {c:v for k,v in char_numbers for c in k}
>>> phone = "JUST 1 NUMBER"
>>> result = "".join(str(char_num_map.get(v,v)) for v in phone.lower())
>>> result
'5878 1 686237'

Answer 2

您的函数getNumber() 返回一个数字，但您没有存储它。要存储它，请将结果分配给一个变量，然后返回它：

def translateNumber():
    phoneNumber = str(input("Enter a string: "))
    for char in phoneNumber:
        if char in    ['A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z']:
            result = getNumber(char)
            return result
        else:
            return char

Answer 3

def getNumber(uppercaseLetter):  
#Create a function to return phone number
    ascii = ord(uppercaseLetter) # get ascii using ord() method
    # returns all the possible digits
    if ascii < 83:
        Number = (ascii - 65)//3+2
    elif ascii == 83:
        Number = 7
    elif ascii >83 and ascii < 97:
        Number = 8
    #If the input char is a digit, returns the digit
    elif isdigit(uppercaseLetter) == True:
        Number = uppercaseLetter
    else: 
        Number = 9
    Number = str(Number)
    return Number 

def main():     # Define the main function
    output = "" # Setting the output as a blank string
    str = input('Enter a string: \n') # Get input from user
    lst = [x for x in str] # convert all char in str to a list
    for x in str:
        # If the char x is alphabet make it to the uppercase
        if isdigit(x) == False and isalnum(x) == True:
           uppercaseLetter = x.upper()
           result = getNumber(uppercaseLetter)
           output = output + result
           if isalnum(x) == False: # If the char x is a digit
               output = output + x
        else:
            output = output + x
    print(output)        
main() # Excute the main function