PDO - “在非对象上调用成员函数 fetch()”

Question

我知道当查询返回 false 时通常会发生错误，但这一次是没有理由的！ （或者只是我犯了一个大错误）

    if(!$security_SenderId){
        $getbaseticketqry = $this->db->prepare("SELECT * FROM `tickets` WHERE `ticket_safeid` = '?'");
        $getbaseticket = $getbaseticketqry->execute(array($ticket_safeid));
    }else{
        $getbaseticketqry = $this->db->prepare("SELECT * FROM `tickets` WHERE `ticket_safeid` = '?' AND `ticket_sender` = '?'");
        $getbaseticket = $getbaseticketqry->execute(array($ticket_safeid, $security_SenderId));
    }

    if($getbaseticket === false){
        return false;
    }else{
        $baseticket = $getbaseticket->fetch(PDO::FETCH_ASSOC);
    }

我在以数组形式返回支持票证信息的函数中有这些行，但正如我所说，当我尝试获取票证信息时会发生错误。我试图通过启用 pdo 调试模式和db->errorInfo() 在 fetch line 之前检查 mysql 错误，但它不起作用。

这可能是什么问题？

编辑：

<?php
error_reporting(E_ALL); ini_set('display_errors', 1);

class TICKET_MANAGER
{
    function __construct($dbhost, $dbname, $dbuser, $dbpass) {
        try{
            $this->db = new PDO("mysql:host=$dbhost;dbname=$dbname;charset=utf8", $dbuser, $dbpass);
            $this->db->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
        }catch(PDOException $e){
            die('Connection failed: ' . $e->getMessage() );
        }
    }

    function viewTicket($ticket_safeid, $security_SenderId = false)
    {
        try{
            if(!$security_SenderId){
                $getbaseticketqry = $this->db->prepare("SELECT * FROM `tickets` WHERE `ticket_safeid` = ?");
                $getbaseticket = $getbaseticketqry->execute(array($ticket_safeid));
            }else{
                $getbaseticketqry = $this->db->prepare("SELECT * FROM `tickets` WHERE `ticket_safeid` = ? AND `ticket_sender` = ?");
                $getbaseticket = $getbaseticketqry->execute(array($ticket_safeid, $security_SenderId));
            }
        }catch(PDOException $e){
            die('Mysql error: ' . $e->getMessage() );
        }
        ...

    }

    ...
}

Answer 1

这是您所有 '?' 周围的引号 - 删除它们。

阅读手册

• http://php.net/pdo.prepared-statements

来自手册：

$stmt = $dbh->prepare("INSERT INTO REGISTRY (name, value) VALUES (?, ?)");

异常应该告诉你这个错误

setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION)

并在您连接到数据库后立即使用。

---

-http://php.net/manual/en/pdo.error-handling.php

try {
    $dbh = new PDO($dsn, $user, $password);
    $dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
} catch (PDOException $e) {
    echo 'Connection failed: ' . $e->getMessage();
}

查询：

try {

// your query

}
    catch(PDOException $e){
     print  $e->getMessage();
    }

---

将error reporting 添加到文件顶部，这将有助于查找错误。

<?php 
error_reporting(E_ALL);
ini_set('display_errors', 1);

// rest of your code

旁注：错误报告只能在暂存阶段完成，而不能在生产阶段完成。