井字游戏逻辑问题答案

【问题标题】：Tic-tac-toe game logic problems井字游戏逻辑问题
【发布时间】：2021-01-17 01:11:27
【问题描述】：

[已编辑] 为简单起见，我将在此处包含整个文件：

choices = ['1', '2', '3', '4', '5', '6', '7', '8', '9']
Is_Current_One = True
won = False
wrongEntryPlayer1 = False
wrongEntryPlayer2 = False
while not won:
    if not wrongEntryPlayer1 and not wrongEntryPlayer2:
        print('\n')
        print('|' + choices[0] + '|' + choices[1] + '|' + choices[2] + '|')
        print('----------')
        print('|' + choices[3] + '|' + choices[4] + '|' + choices[5] + '|')
        print('----------')
        print('|' + choices[6] + '|' + choices[7] + '|' + choices[8] + '|')
    # above code is to print board layouts
    if Is_Current_One:
        print("Player 1's turn.\nChoose a number to put an X there.")
        try:
            choice = int(input("> ").strip())
            wrongEntryPlayer1 = False
        except ValueError:
            print("Please enter only valid fields from board (0-8)")
            wrongEntryPlayer1 = True
            continue
    else:
        print("Player 2's turn.\nChoose a number to put an O there.")
        try:
            choice = int(input("> ").strip())
            wrongEntryPlayer2 = False
        except ValueError:
            print("Please enter only valid fields from board (0-8)")
            wrongEntryPlayer2 = True
            continue

    if Is_Current_One:
        if choices[choice - 1] == int:
            try:
                choices[choice - 1] = 'X'
                wrongEntryPlayer1 = False
            except IndexError:
                print("Please enter only valid fields from board (0-8)")
                wrongEntryPlayer1 = True
        else:
            print("Please choose a number that is empty.")
            wrongEntryPlayer1 = True
    else:
        if choices[choice - 1] == int:
            try:
                choices[choice - 1] = 'O'
                wrongEntryPlayer2 = False
            except IndexError:
                print("Please enter only valid fields from board (0-8)")
                wrongEntryPlayer2 = True
        else:
            print("Please choose a number that is empty.")
            wrongEntryPlayer2 = True
    # code to toggle between True and False
    Is_Current_One = not Is_Current_One

    for pos_x in range(0, 3):
        pos_y = pos_x * 3

        # for row condition:
        if (choices[pos_y] == choices[(pos_y + 1)]) and (
                choices[pos_y] == choices[(pos_y + 2)]):
            won = True

        # column condition:
        if (choices[pos_x] == choices[(pos_x + 3)]) and (
                choices[pos_x] == choices[(pos_x + 6)]):
            won = True
    if ((choices[0] == choices[4] and choices[0] == choices[8])
            or (choices[2] == choices[4] and choices[4] == choices[6])):
        won = True

print("Player " + str(int(Is_Current_One + 1)) + " won, Congratulations!")

如果你真的读过代码，你会发现我在做一个井字游戏。我已经声明了两个布尔变量：wrongEntryPlayer1 和wrongEntryPlayer2，最初默认设置为False，因为游戏刚刚开始。在玩这个游戏时，玩家需要输入一个整数，在游戏板中显示，在其中放置一个X或O。如果玩家没有输入一个整数，程序就会崩溃，我不想这样。相反，我使用try 语句并在他们没有输入整数时打印一条用户友好的消息。发生这种情况时，我不想让 Python 重新打印游戏板，所以当玩家输入错误的值时，我将相应的 wrongEntryPlayer 变量设置为 True。这样，如果任何一个玩家输入了错误的值，我将完全跳过打印游戏板。

但是，当我尝试运行它并在第一回合输入错误的值，然后输入正确的值时，游戏板仍然不显示。即使轮到玩家 2，游戏板仍然没有打印出来。

当玩家输入正确的值（整数）时，游戏板仍然不显示。

另外，当玩家输入已经被其他玩家占用的值时，程序应该提示玩家再次输入。相反，它只是跳过玩家的回合。

我是python初学者，所以有些代码可能看起来很傻。谁能帮助我并向我解释如何解决这个问题？谢谢！感谢 Sanetro，我原来的问题得到了解决。现在发生了另一个错误。详细问题发布在 Sanetro 答案的评论部分。我在这里包含我的详细编辑代码。

choices = ['1', '2', '3', '4', '5', '6', '7', '8', '9']
Is_Current_One = True
won = False
wrongEntryPlayer1 = False
wrongEntryPlayer2 = False
while not won:
    if not wrongEntryPlayer1 and not wrongEntryPlayer2:
        print('\n')
        print('|' + choices[0] + '|' + choices[1] + '|' + choices[2] + '|')
        print('----------')
        print('|' + choices[3] + '|' + choices[4] + '|' + choices[5] + '|')
        print('----------')
        print('|' + choices[6] + '|' + choices[7] + '|' + choices[8] + '|')
    # above code is to print board layouts
    if Is_Current_One:
        print("Player 1's turn.\nChoose a number to put an X there.")
        try:
            choice = int(input("> ").strip())
            wrongEntryPlayer1 = False
        except ValueError:
            print("Please enter only valid fields from board (0-8)")
            wrongEntryPlayer1 = True
            continue
        except IndexError:
            print("Please enter only valid fields from board (0-8)")
            wrongEntryPlayer1 = True
            continue
    else:
        print("Player 2's turn.\nChoose a number to put an O there.")
        try:
            choice = int(input("> ").strip())
            wrongEntryPlayer2 = False
        except ValueError:
            print("Please enter only valid fields from board (0-8)")
            wrongEntryPlayer2 = True
            continue
        except IndexError:
            print("Please enter only valid fields from board (0-8)")
            wrongEntryPlayer2 = True
            continue
    if Is_Current_One:
        if choices[choice - 1].isnumeric():
            try:
                choices[choice - 1] = 'X'
                wrongEntryPlayer1 = False
            except ValueError:
                print("Please enter only valid fields from board (0-8)")
                wrongEntryPlayer1 = True
                continue
            except IndexError:
                print("Please enter only valid fields from board (0-8)")
                wrongEntryPlayer1 = True
                continue
        else:
            print("Please choose a number that is empty.")
            wrongEntryPlayer1 = True
    else:
        if choices[choice - 1].isnumeric():
            try:
                choices[choice - 1] = 'O'
                wrongEntryPlayer2 = False
            except ValueError:
                print("Please enter only valid fields from board (0-8)")
                wrongEntryPlayer2 = True
                continue
            except IndexError:
                print("Please enter only valid fields from board (0-8)")
                wrongEntryPlayer2 = True
                continue
        else:
            print("Please choose a number that is empty.")
            wrongEntryPlayer2 = True

    # code to toggle between True and False
    if wrongEntryPlayer1 == False and wrongEntryPlayer2 == False:
        Is_Current_One = not Is_Current_One

    for pos_x in range(0, 3):
        pos_y = pos_x * 3

        # for row condition:
        if (choices[pos_y] == choices[(pos_y + 1)]) and (
                choices[pos_y] == choices[(pos_y + 2)]):
            won = True

        # column condition:
        if (choices[pos_x] == choices[(pos_x + 3)]) and (
                choices[pos_x] == choices[(pos_x + 6)]):
            won = True
    if ((choices[0] == choices[4] and choices[0] == choices[8])
            or (choices[2] == choices[4] and choices[4] == choices[6])):
        won = True

print("Player " + str(int(Is_Current_One + 1)) + " won, Congratulations!")

[编辑 2] 好的，Sanetro，这实际上是不是最终编辑。我正在制作退出命令。当播放器类型>退出时，程序退出。我最初认为这真的很简单。你做一个while循环，当玩家类型退出时打破循环，然后就是这样！嗯，它不简单（至少对我来说）。由于 choice = input(.....) 是 in 循环，我不能将它放在循环之外（或在声明选择变量之前），这很糟糕。我在顶部创建了一个新变量：exitTrigger 并将新行放入 while 循环中。它现在不起作用。当玩家类型退出时，它只是说请只输入有效字段。可能是因为except语句仍然有效，我想添加一个条件来触发except语句，并且我只想要exitTrigger为True时的except语句。我可以这样做吗？谢谢。

choices = ['1', '2', '3', '4', '5', '6', '7', '8', '9', '10', '11', '12', '13', '14', '15', '16']
Is_Current_One = True
won = False
wrongEntryPlayer1 = False
wrongEntryPlayer2 = False
exitTrigger = False
while not won and not exitTrigger:
    if not wrongEntryPlayer1 and not wrongEntryPlayer2:
        print("Type exit to quit game")
        print('\n')
        print('|' + choices[0] + ' |' + choices[1] + ' |' + choices[2] + ' |' + choices[3] + ' |')
        print('-------------')
        print('|' + choices[4] + ' |' + choices[5] + ' |' + choices[6] + ' |' + choices[7] + ' |')
        print('-------------')
        print('|' + choices[8] + ' |' + choices[9] + '|' + choices[10] + '|' + choices[11] + '|')
        print('-------------')
        print('|' + choices[12] + '|' + choices[13] + '|' + choices[14] + '|' + choices[15] + '|')
    # above code is to print board layouts
    if Is_Current_One:
        print("Player 1's turn.\nChoose a number to put an X there.")
        try:
            choice = int(input("> ").strip())
            if choice == "exit":
                exitTrigger = True
            else:
                wrongEntryPlayer1 = False
        except ValueError:
            if not exitTrigger:
                print("Please enter only valid fields from board (1-16)")
                wrongEntryPlayer1 = True
                continue
        except IndexError:
            if not exitTrigger:
                print("Please enter only valid fields from board (1-16)")
                wrongEntryPlayer1 = True
                continue
    else:
        print("Player 2's turn.\nChoose a number to put an O there.")
        try:
            choice = int(input("> ").strip())
            if choice == "exit":
                exitTrigger = True
            else:
                wrongEntryPlayer2 = False
        except ValueError:
            print("Please enter only valid fields from board (1-16)")
            wrongEntryPlayer2 = True
            continue
        except IndexError:
            if not exitTrigger:
                print("Please enter only valid fields from board (1-16)")
                wrongEntryPlayer2 = True
                continue

    if not exitTrigger:
        if Is_Current_One:
            try:  # <============ HERE
                if choices[choice - 1].isnumeric():
                    try:
                        choices[choice - 1] = 'X'
                        wrongEntryPlayer1 = False
                    except ValueError:
                        print("Please enter only valid fields from board (1-16)")
                        wrongEntryPlayer1 = True
                        continue
                    except IndexError:
                        print("Please enter only valid fields from board (1-16)")
                        wrongEntryPlayer1 = True
                        continue
                else:
                    print("Please choose a number that is empty.")
                    wrongEntryPlayer1 = True
            except:  # <============ HERE
                print("Please enter only valid fields from board (1-16)")
                wrongEntryPlayer1 = True
                continue
        else:
            try:  # <============ HERE
                if choices[choice - 1].isnumeric():
                    try:
                        choices[choice - 1] = 'O'
                        wrongEntryPlayer2 = False
                    except ValueError:
                        print("Please enter only valid fields from board (1-16)")
                        wrongEntryPlayer2 = True
                        continue
                    except IndexError:
                        print("Please enter only valid fields from board (1-16)")
                        wrongEntryPlayer2 = True
                        continue
                else:
                    print("Please choose a number that is empty.")
                    wrongEntryPlayer2 = True
            except:  # <============ HERE
                print("Please enter only valid fields from board (1-16)")
                wrongEntryPlayer2 = True
                continue

    # code to toggle between True and False
    if not exitTrigger:
        if wrongEntryPlayer1 == False and wrongEntryPlayer2 == False:
            Is_Current_One = not Is_Current_One

        for pos_x in range(0, 4):
            pos_y = pos_x * 4

            # for row condition:
            if (choices[pos_y] == choices[(pos_y + 1)]) and (
                    choices[pos_y] == choices[(pos_y + 2)]) and (
                    choices[pos_y] == choices[(pos_y + 3)]):
                won = True

            # column condition:
            if (choices[pos_x] == choices[(pos_x + 4)]) and (
                    choices[pos_x] == choices[(pos_x + 8)]) and (
                    choices[pos_x] == choices[(pos_x + 12)]):
                won = True
        if ((choices[0] == choices[5] and choices[0] == choices[10] and choices[0] == choices[15])
                or (choices[3] == choices[6] and choices[3] == choices[9] and choices[3] == choices[12])):
            won = True
if won:
    print('\n')
    print('|' + choices[0] + ' |' + choices[1] + ' |' + choices[2] + ' |' + choices[3] + ' |')
    print('-------------')
    print('|' + choices[4] + ' |' + choices[5] + ' |' + choices[6] + ' |' + choices[7] + ' |')
    print('-------------')
    print('|' + choices[8] + ' |' + choices[9] + '|' + choices[10] + '|' + choices[11] + '|')
    print('-------------')
    print('|' + choices[12] + '|' + choices[13] + '|' + choices[14] + '|' + choices[15] + '|')
    # above code is to print board layouts
    print("Player " + str(int(Is_Current_One + 1)) + " won, Congratulations!")
if exitTrigger:
    print("Game quited")

顺便说一句，游戏板现在是 4*4 :D

【问题讨论】：

标签： python python-3.x

【解决方案1】：

您的代码实际上存在两个问题 - 首先，您请求帮助的问题是由切换标志 Is_Current_One 引起的，即使玩家输入“错误”输入也是如此。换句话说，当玩家一输入“asdf”时，我们希望他们有机会再次输入“好”输入，而不是立即切换到玩家二。将if 块放在读取if not wrongEntryPlayer1 and not wrongEntryPlayer2: 的那一行上。

第二个更大的问题是，您对玩家输入是否为int 的类型检查不起作用。首先，choices[choice - 1] == int 将数组中的值与类型进行比较，该类型始终为False。其次，即使函数isinstance(choices[choice-1], int) 也不起作用，因为选项的每个成员都是字符串类型。因此，您应该使用字符串方法choices[choice-1].isnumeric()，它将确定数组中的字符串是否为数字。（或者，您可以只测试它不是 x 或 o，但这更符合 Pythonic。）

我测试了这些更改，它们似乎有效。 pastebin

【讨论】：

谢谢！我忘记了我实际上是在将值与类型进行比较。现在它完美运行了！

【解决方案2】：

[编辑] 我做了一些修复，一切正常。

choices = ['1', '2', '3', '4', '5', '6', '7', '8', '9']
Is_Current_One = True
won = False
wrongEntryPlayer1 = False
wrongEntryPlayer2 = False
while not won:
    if not wrongEntryPlayer1 and not wrongEntryPlayer2:
        print('\n')
        print('|' + choices[0] + '|' + choices[1] + '|' + choices[2] + '|')
        print('----------')
        print('|' + choices[3] + '|' + choices[4] + '|' + choices[5] + '|')
        print('----------')
        print('|' + choices[6] + '|' + choices[7] + '|' + choices[8] + '|')
    # above code is to print board layouts
    if Is_Current_One:
        print("Player 1's turn.\nChoose a number to put an X there.")
        try:
            choice = int(input("> ").strip())
            wrongEntryPlayer1 = False
        except ValueError:
            print("Please enter only valid fields from board (0-8)")
            wrongEntryPlayer1 = True
            continue
    else:
        print("Player 2's turn.\nChoose a number to put an O there.")
        try:
            choice = int(input("> ").strip())
            wrongEntryPlayer2 = False
        except ValueError:
            print("Please enter only valid fields from board (0-8)")
            wrongEntryPlayer2 = True
            continue

    if Is_Current_One:
        if choices[choice - 1].isnumeric():
            try:
                choices[choice - 1] = 'X'
                wrongEntryPlayer1 = False
            except IndexError:
                print("Please enter only valid fields from board (0-8)")
                wrongEntryPlayer1 = True
        else:
            print("Please choose a number that is empty.")
            wrongEntryPlayer1 = True
    else:
        if choices[choice - 1].isnumeric():
            try:
                choices[choice - 1] = 'O'
                wrongEntryPlayer2 = False
            except IndexError:
                print("Please enter only valid fields from board (0-8)")
                wrongEntryPlayer2 = True
        else:
            print("Please choose a number that is empty.")
            wrongEntryPlayer2 = True

    # code to toggle between True and False
    if wrongEntryPlayer1 == False and wrongEntryPlayer2 == False:
        Is_Current_One = not Is_Current_One

    for pos_x in range(0, 3):
        pos_y = pos_x * 3

        # for row condition:
        if (choices[pos_y] == choices[(pos_y + 1)]) and (
                choices[pos_y] == choices[(pos_y + 2)]):
            won = True

        # column condition:
        if (choices[pos_x] == choices[(pos_x + 3)]) and (
                choices[pos_x] == choices[(pos_x + 6)]):
            won = True
    if ((choices[0] == choices[4] and choices[0] == choices[8])
            or (choices[2] == choices[4] and choices[4] == choices[6])):
        won = True

print("Player " + str(int(Is_Current_One + 1)) + " won, Congratulations!")

所以，我想为一些错误道歉。我在互联网上找到了解决方案。在第 35 行 if choices[choice - 1] == int: 你必须像这样更改 if choices[choice - 1].isnumeric():，大多数变量都被视为对象。如果您想尝试使用type()，您将收到错误消息。接下来我删除了我的choices_closed这些东西'='。这是完全没有必要的。你的想法比我做的好。我说的是条件if it's different then intiger it's fill'。我没有看到这几行代码：

    # code to toggle between True and False
    Is_Current_One = not Is_Current_One

我马上写了：

    # code to toggle between True and False
    if wrongEntryPlayer1 == False and wrongEntryPlayer2 == False:
        Is_Current_One = not Is_Current_One

我以为你和我一样困，而你没有注意到这一点。我必须说这是我的错误

[编辑] 我在这里添加了一些例外：

    if Is_Current_One:
        try: # <============ HERE
            if choices[choice - 1].isnumeric():
                try:
                    choices[choice - 1] = 'X'
                    wrongEntryPlayer1 = False
                except ValueError:
                    print("Please enter only valid fields from board (0-8)")
                    wrongEntryPlayer1 = True
                    continue
                except IndexError:
                    print("Please enter only valid fields from board (0-8)")
                    wrongEntryPlayer1 = True
                    continue
            else:
                print("Please choose a number that is empty.")
                wrongEntryPlayer1 = True
        except: # <============ HERE
            print("Please enter only valid fields from board (0-8)")
            wrongEntryPlayer1 = True
            continue
    else:
        try: # <============ HERE
            if choices[choice - 1].isnumeric():
                try:
                    choices[choice - 1] = 'O'
                    wrongEntryPlayer2 = False
                except ValueError:
                    print("Please enter only valid fields from board (0-8)")
                    wrongEntryPlayer2 = True
                    continue
                except IndexError:
                    print("Please enter only valid fields from board (0-8)")
                    wrongEntryPlayer2 = True
                    continue
            else:
                print("Please choose a number that is empty.")
                wrongEntryPlayer2 = True
        except: # <============ HERE
            print("Please enter only valid fields from board (0-8)")
            wrongEntryPlayer2 = True
            continue

也许这是最后的编辑：P 当您发现更多内容时，我会尽力提供帮助。

【讨论】：

我搞错了。我醒来时会做这个
我注意到当玩家选择一个被占用的空间时，他们仍然会跳过他们的回合。这就是你说的问题吗？
是的，但现在我确定现在可以了。很难阅读，因为凌晨 4 点我的眼睛几乎闭上了。我重写了所有文本，所以请检查一下。
您好，很抱歉再次打扰。我尝试了各种不好的答案，最后发现了另一个错误。如果输入大于 9 的值，则会引发索引错误。您可以看到有两个if Is_Current_One 语句。 try 和 except 仅包含 ValueError，第二个 if Is_Current_One 语句仅包含 IndexError。所以我分别在第一个和第二个语句中添加了 IndexError 和 ValueError。尽管如此，这仍然行不通。 > 11 Traceback（最近一次调用最后一次）：第 42 行，在如果选择 [choice - 1].isnumeric(): IndexError: list index out of range
我已经编辑了我的问题并包含了我编辑的代码。

【解决方案3】：

我认为不是使用

 if not wrongEntryPlayer1 and not wrongEntryPlayer2:

你应该使用：

if wrongEntryPlayer1 or wrongEntryPlayer2:

这将修复打印板的部分。

【讨论】：