【发布时间】:2020-03-19 21:22:54
【问题描述】:
假设我有以下数据库架构
CREATE TABLE employee(
id BIGINT AUTO_INCREMENT PRIMARY KEY,
name VARCHAR(50) NOT NULL,
hrid VARCHAR (50)
);
CREATE TABLE territory(
id BIGINT PRIMARY KEY,
name varchar (50)
);
CREATE TABLE transcode(
id BIGINT AUTO_INCREMENT PRIMARY KEY,
code VARCHAR (10) NOT NULL
);
create table employee_territory_function(
employee_id BIGINT NOT NULL,
territory_id BIGINT NOT NULL,
transcode_id BIGINT NOT NULL,
PRIMARY KEY (employee_id,territory_id),
CONSTRAINT employeeref FOREIGN KEY (employee_id) REFERENCES employee (id),
CONSTRAINT territoryref FOREIGN KEY (territory_id) REFERENCES territory (id) ,
CONSTRAINT transcoderef FOREIGN KEY (transcode_id) REFERENCES transcode (id)
);
现在我有以下 JPA 映射实体
员工实体
@Entity
public class Employee implements Serializable {
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private long id;
private String name;
private String hrid;
@OneToMany(fetch = FetchType.LAZY, mappedBy = "employee", cascade = CascadeType.ALL)
private Set<EmployeeTerritoryFunction> employeeTerritoryFunctionList = new HashSet<>();
//getters and setters
}
领土实体:
@Entity
public class Territory implements Serializable {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private long id;
private String name;
// getters and setters for all field
}
转码实体:
@Entity
public class Territory implements Serializable {
@Id
private long id;
private String name;
//getters and setters
}
EmployeeTerritoryFunction 实体(复合键表)
@Entity
@IdClass(value = EmployeeTerritoryFunctionPK.class)
public class EmployeeTerritoryFunction implements Serializable {
private static final long serialVersionUID = 1L;
@Id
@ManyToOne
private Employee employee;
@Id
@ManyToOne
private Territory territory;
@ManyToOne
@JoinColumn(name = "transcode_id", referencedColumnName = "id")
private Transcode transcode;
//getters and setters
}
EmployeeTerritoryFunction pk
public class EmployeeTerritoryFunctionPK implements Serializable {
private static final long serialVersionUID = 1L;
private Long employee;
private Long territory;
//getters and setters, no args constructor, equals and hashcode
}
样本插入下方
Employee employee = this.employeeRepository.findByHrid("111");
if (employee == null) {
employee = new Employee();
employee.setName("Marie");
employee.setHrid("333");
}
Territory territory = new Territory();
territory.setId(2L);
territory.setName("T2");
Territory territory2 = new Territory();
territory2.setId(3L);
territory2.setName("T3");
Transcode transcode = this.transcodeRepository.findByCode("ASC");
Transcode transcode2 = this.transcodeRepository.findByCode("CC");
EmployeeTerritoryFunction employeeTerritoryFunction1 = new EmployeeTerritoryFunction();
employeeTerritoryFunction1.setTranscode(transcode);
employeeTerritoryFunction1.setTerritory(territory);
employeeTerritoryFunction1.setEmployee(employee);
employee.getEmployeeTerritoryFunctionList().add(employeeTerritoryFunction1);
EmployeeTerritoryFunction employeeTerritoryFunction2 = new EmployeeTerritoryFunction();
employeeTerritoryFunction2.setTranscode(transcode2);
employeeTerritoryFunction2.setTerritory(territory2);
employeeTerritoryFunction2.setEmployee(employee);
employee.getEmployeeTerritoryFunctionList().add(employeeTerritoryFunction2);
employeeRepository.save(employee);
当我只使用新对象运行上面的代码时,我没有问题,因为 hibernate 会自动插入员工、区域和employee_territory_function 列表,但是当我第一次删除所有现有区域时,employee_territory_function 并尝试使用现有员工插入, hibernate 不能自动插入或更新员工、自动插入区域、employee_territory_function。 下面的错误
Caused by: org.hibernate.LazyInitializationException: failed to lazily initialize a collection of role: com.example.demo.Employee.employeeTerritoryFunctionList, could not initialize proxy - no Session
当我将 oneToMany 提取类型替换为 EAGER 时,出现以下错误
Caused by: javax.persistence.EntityNotFoundException: Unable to find com.example.demo.Territory with id 3
hibernate 尝试查询 Territory 表的接缝,但我不这样做,因为我删除了 Territory 和 EmployeeTerritoryFunction 表上的所有数据,并且只有员工现有数据没有被删除。
请问如何解决?
【问题讨论】:
-
你可以看看这个答案:stackoverflow.com/a/22822283/1566345
-
感谢您的回复。根据链接的答案,我应该使用 EAGER oneToMany 获取类型。但仍然出现另一个错误。请在我编辑的问题中找到@BrianVosburgh
标签: java spring hibernate jpa composite-primary-key