选择所有包含一件以上商品的订单并检查所有商品状态

Question

我有 2 张桌子：

订单：

Id   |  Status
-----+--------
 1   |      OK
 2   | WAITING
 3   | WAITING
 4   |      OK
 5   |      OK
 6   |      OK

还有 Order_details：

Id   |  Order_Id  |  Status
-----+------------+--------
 1   |         1  |      S1
 2   |         1  |      S1
 3   |         2  |      S1
 4   |         4  |      S2
 5   |         4  |      S2
 6   |         4  |      S3
 7   |         5  |      S1
 8   |         5  |      S1

我需要做的是选择所有具有多个 Order_detail 的订单，并且订单状态必须为“OK”，并且每个 order_detail 必须在（S1，S2）中具有状态

我做过这样的事情：

SELECT O.Id FROM Orders O 
            JOIN Order_details OD 
                ON O.Id=OD.Order_Id
WHERE O.Status='OK' AND OD.Status IN ('S1','S2')
GROUP BY O.Id
HAVING count(DISTINCT OD.Id)>1

但这会返回具有多个 Order_details 满足条件的所有订单。

我确定这部分没问题：

SELECT O.Id FROM Orders O 
            JOIN Order_details OD 
                ON O.Id=OD.Order_Id
WHERE O.Status='OK'
GROUP BY O.Id
HAVING count(DISTINCT OD.Id)>1

但我必须检查上述订单的每个 Order_detail 是否有状态 IN (S1, S2)。

因此，如果订单将有 2 个详细信息，其中一个的 status=S1 和第二个 S3，则应跳过此订单。

Answer 1

SELECT O.Id 
FROM Orders O 
JOIN Order_details OD ON O.Id=OD.Order_Id
WHERE O.Status='OK'
GROUP BY O.Id
HAVING count(DISTINCT OD.Id)>1
AND SUM(CASE WHEN OD.Status NOT IN ('S1','S2') 
             THEN 1 
             ELSE 0 
        END) = 0

Answer 2

select O.id
from orders O inner join order_details OD
on O.Id=OD.Order_Id and O.Status='OK' AND OD.Status IN ('S1','S2')
GROUP BY O.Id
HAVING count(DISTINCT OD.Id)>1