向存储在 spring 安全上下文中的主体对象添加其他详细信息

Question

我正在使用 Spring 3.0 和 Spring Security 3。我能够使用 Spring Security 对数据库进行用户身份验证。使用：

SecurityContextHolder.getContext().getAuthentication().getPrincipal()

我能够检索当前登录用户的用户名。我希望添加其他详细信息，例如用户 ID 和模块访问存储在 Spring Security 上下文中的主体对象，以便我以后可以检索它。如何向主体对象添加其他详细信息，然后如何在 jsp 或 java 类中检索它。如果可能，请提供适当的代码 sn-p。

编辑：我正在使用 JDBC 访问我的数据库。

提前致谢。

Answer 1

为了向经过身份验证的用户添加更多详细信息。您需要首先创建自己的 User 对象实现，该对象应该扩展 spring security User 对象。之后，您可以将要添加的属性添加到经过身份验证的用户。完成此操作后，您需要在 UserDetailService 中返回用户对象的实现（如果您不使用 LDAP 进行身份验证）。此链接提供了向经过身份验证的用户添加更多详细信息的详细信息--

http://javahotpot.blogspot.com/2013/12/spring-security-adding-more-information.html

Answer 2

这是你需要的：

1. 扩展 spring User (org.springframework.security.core.userdetails.User) 类以及您需要的任何属性。
2. 拉伸弹簧UserDetailsService (org.springframework.security.core.userdetails.UserDetailsService) 并填充上面的对象。覆盖 loadUserByUsername 并返回您的扩展用户类
3. 在AuthenticationManagerBuilder 中设置您的自定义UserDetailsService

例如

public class CurrentUser extends User{

   //This constructor is a must
    public CurrentUser(String username, String password, boolean enabled, boolean accountNonExpired,
            boolean credentialsNonExpired, boolean accountNonLocked,
            Collection<? extends GrantedAuthority> authorities) {
        super(username, password, enabled, accountNonExpired, credentialsNonExpired, accountNonLocked, authorities);
    }
    //Setter and getters are required
    private String firstName;
    private String lastName;

}

自定义用户详细信息可以是：

@Service("userDetailsService")
public class CustomUserDetailsService implements UserDetailsService {

@Override
public UserDetails loadUserByUsername(final String username) throws UsernameNotFoundException {

    //Try to find user and its roles, for example here we try to get it from database via a DAO object
   //Do not confuse this foo.bar.User with CurrentUser or spring User, this is a temporary object which holds user info stored in database
    foo.bar.User user = userDao.findByUserName(username);

    //Build user Authority. some how a convert from your custom roles which are in database to spring GrantedAuthority
    List<GrantedAuthority> authorities = buildUserAuthority(user.getUserRole());

    //The magic is happen in this private method !
    return buildUserForAuthentication(user, authorities);

}


//Fill your extended User object (CurrentUser) here and return it
private User buildUserForAuthentication(foo.bar.User user, 
List<GrantedAuthority> authorities) {
    String username = user.getUsername();
    String password = user.getPassword();
    boolean enabled = true;
    boolean accountNonExpired = true;
    boolean credentialsNonExpired = true;
    boolean accountNonLocked = true;

    return new CurrentUser(username, password, enabled, accountNonExpired, credentialsNonExpired,
            accountNonLocked, authorities);
   //If your database has more information of user for example firstname,... You can fill it here 
  //CurrentUser currentUser = new CurrentUser(....)
  //currentUser.setFirstName( user.getfirstName() );
  //.....
  //return currentUser ;
}

private List<GrantedAuthority> buildUserAuthority(Set<UserRole> userRoles) {

    Set<GrantedAuthority> setAuths = new HashSet<GrantedAuthority>();

    // Build user's authorities
    for (UserRole userRole : userRoles) {
        setAuths.add(new SimpleGrantedAuthority(userRole.getRole()));
    }

    return new ArrayList<GrantedAuthority>(setAuths);
}

}

配置spring安全上下文

@Configuration
@EnableWebSecurity
@PropertySource("classpath://configs.properties")
public class SecurityContextConfig extends WebSecurityConfigurerAdapter {

    @Autowired
    @Qualifier("userDetailsService")
    private UserDetailsService userDetailsService;

    @Autowired
    public void configureGlobal(AuthenticationManagerBuilder auth) throws Exception {
        auth.userDetailsService(userDetailsService);
    }

一切都搞定了！

您可以致电(CurrentUser)getAuthentication().getPrincipal() 获取新的CurrentUser 或设置一些属性。

Answer 3

（我假设你有一个基本的 Spring Security 配置并且知道基本组件是如何协同工作的）

最“正确”的方法是提供您自己的AuthenticationProvider 实现，返回自定义Authentication 实现。然后你可以用你需要的一切填写这个Authentication 实例。例如：

public class MyAuthentication extends UsernamePasswordAuthenticationToken implements Authentication {

    public MyAuthentication(Object principal, Object credentials, int moduleCode) {
        super(principal, credentials);
        this.moduleCode = moduleCode;
    }

    public MyAuthentication(Object principal, Object credentials,  Collection<? extends GrantedAuthority> authorities,int moduleCode) {
        super(principal, credentials, authorities);
        this.moduleCode = moduleCode;
    }

    private int moduleCode;

    public getModuleCode() {
        return moduleCode;
    }   
}


public class MyAuthenticationProvider extends DaoAuthenticationProvider {

    private Collection<GrantedAuthority> obtainAuthorities(UserDetails user) {
        // return granted authorities for user, according to your requirements
    }

    private int obtainModuleCode(UserDetails user) {
        // return moduleCode for user, according to your requirements
    }

    @Override
    public Authentication createSuccessAuthentication(Object principal, Authentication authentication, UserDetails user) {
        // Suppose this user implementation has a moduleCode property
        MyAuthentication result = new MyAuthentication(authentication.getPrincipal(),
                                                       authentication.getCredentials(),
                                                       obtainAuthorities(user),
                                                       obtainModuleCode(user));
        result.setDetails(authentication.getDetails());
        return result;
    }
}

然后，在applicationContext.xml:

<authentication-manager>
    <authentication-provider ref="myAuthenticationProvider">
</authentication-manager>

<bean id="myAuthenticationProvider" class="MyAuthenticationProvider" scope="singleton">
    ...
</bean>

我想您可以通过提供 AuthenticationDetails 和 AuthenticationDetailsSource 的自定义实现来使其正常工作，但我认为这是一种不太干净的方法。

Answer 4

您需要做的“唯一”事情是创建自己的 UserDetailsService 实现，它返回您自己的 UserDetails 对象实现。

有关实现基于 JPA 的 UserDetailsService 的教程，请参阅 here。