我的代码一直在打印“ [Ljava.lang.String;@4e50df2e”，不太确定该放在哪里以及如何放置 toString()

Question

** 如您所见，我编写了一个程序来打印同一分支和学院的学生记录，用户在其中输入姓名和卷号。

我尝试从我的 IDE 生成 toString()，但它仍然显示“[Ljava.lang.String;@4e50df2e”这些...请帮我摆脱这个...谢谢。**

class Stur
{
static String branchcode="C04";
static String branch="Computer Sc. & Eng. ";
static String rollcode="18020";
static String collegeName="Kalaniketan Polytechnic College";

String rollno[],name[];

Stur(String n[],String r[])
{
rollno=r;
name=n;


System.out.println(name+" \t "+rollcode+""+branchcode+""+rollno+" \t"+branch+""+collegeName);

}
}   



class staticVar1    //main method class
{
public static void main(String ujyg[])
 
{
int j=0, i=0;

Scanner object=new Scanner(System.in);

System.out.println("how many Students ");
int n=object.nextInt();
String arr[]=new String [n];


for(i=0;i<arr.length;i++)
{
    System.out.print("Enter roll number:");
    arr[i]=object.next();

    System.out.print("Enter Name:");
    arr[i]=object.next();
}

System.out.println("Name \t Roll Number \t   Branch \t\t College\n");


for(j=0;j<arr.length;j++)
{
Stur st=new Stur(new String[i], new String[i]);      

}}
}

期待这样的输出

Name    Roll Number     Branch    College

Anf   18020C0406     Computer Sc. & Eng. Kalaniketan Polytechnic College 
xyz   18020C0402     Computer Sc. & Eng. Kalaniketan Polytechnic College
Ad    18020C0405     Computer Sc. & Eng. Kalaniketan Polytechnic College 
Ax    18020C0401     Computer Sc. & Eng. Kalaniketan Polytechnic College 

Answer 1

请查找更新的代码。

class Stur
{
  static String branchcode="C04";
  static String branch="Computer Sc. & Eng. ";
  static String rollcode="18020";
  static String collegeName="Kalaniketan Polytechnic College";

  String rollno,name;

  Stur(String n,String r)
  {
    rollno=r;
    name=n;
    System.out.println(name + "\t" + rollcode+branchcode+rollno + "\t" + branch + " " + collegeName);
  }
}   

class staticVar1    //main method class
{
  public static void main(String ujyg[]) 
  {
    int j=0, i=0;

    Scanner object=new Scanner(System.in);

    System.out.println("how many Students ");
    int n=object.nextInt();
    String nameArr[]=new String [n];
    String rollnoArr[]=new String [n];


    for(i=0;i<n;i++)
    {
      System.out.print("Enter roll number:");
      rollnoArr[i]=object.next();

      System.out.print("Enter Name:");
      nameArr[i]=object.next();
    }

    System.out.println("Name \t Roll Number \t   Branch \t\t College\n");

    Stur st[] = new Stur[n];
    for(j=0;j<n;j++)
    {
      st[j] = new Stur(nameArr[j], rollnoArr[j]);      

    }
  }
}

你试图直接打印一个数组，所以它给你对象哈希码和类名。如果你想像你提到的那样输出，你需要一个一个地打印数组的元素。