【发布时间】:2016-09-10 05:17:42
【问题描述】:
我正在开发 UWP 应用。在我的应用程序中有 gridview,我想开发它,就像有人点击 gridview 项目然后出现共享选项一样。我已经完成了一些编码部分,但我得到了空点异常。任何人都可以帮助我处理此代码...
XAML:
<Grid Background="{ThemeResource ApplicationPageBackgroundThemeBrush}">
<GridView x:Name="gridview" ItemClick="gridviewitemclick" IsItemClickEnabled="True" >
<GridView.ItemTemplate>
<DataTemplate>
<Image Source="{Binding image}" Margin="2" Height="144" Width="256"/>
</DataTemplate>
</GridView.ItemTemplate>
</GridView>
</Grid>
C#类:
public sealed partial class MainPage : Page
{
private GridView imageitem;
public MainPage()
{
this.InitializeComponent();
loaddata();
DataTransferManager dataTransferManager = DataTransferManager.GetForCurrentView();
dataTransferManager.DataRequested += new TypedEventHandler<DataTransferManager, DataRequestedEventArgs>(this.ShareImageHandler);
}
private void loaddata()
{
List<Class1> listimage = new List<Class1>
{
new Class1 {image="ms-appx:///images/Blo.png" },
new Class1 {image="ms-appx:///images/Bun.png" },
new Class1 {image="ms-appx:///images/Cght.png" },
new Class1 {image="ms-appx:///images/rld.png" },
new Class1 {image="ms-appx:///images/Usa.png" },
new Class1 {image="ms-appx:///images/Wing.png" },
};
gridview.ItemsSource = listimage;
}
private async void ShareImageHandler(DataTransferManager sender, DataRequestedEventArgs e)
{
DataRequest request = e.Request;
DataRequestDeferral deferral = request.GetDeferral();
try
{
StorageFile imagefiles = await Package.Current.InstalledLocation.GetFileAsync(imageitem.SelectedItem.ToString());
request.Data.SetBitmap(RandomAccessStreamReference.CreateFromFile(imagefiles));
}
catch
{
request.FailWithDisplayText("Select an image you would like to share and try again.");
}
finally
{
deferral.Complete();
}
}
private void gridviewitemclick(object sender, ItemClickEventArgs e)
{
DataTransferManager.ShowShareUI();
}
}
【问题讨论】: