【发布时间】：2018-11-11 18:55:39
【问题描述】：
我使用 JavaFX 制作了一个棋盘，并将所有图块设置为 GridPane 的子项，有没有办法可以访问这些图块并使用 GridPane 索引更改它们的属性？
我试图通过瓷砖矩阵访问它来更改一个瓷砖的颜色属性，但它不会更改 GridPane 中显示的瓷砖。
.getChildren() 方法返回一个节点列表，一旦 tile 对象成为节点，我就无法访问它的方法。
这是我的 Tile 类：
package chess.Board;
import static chess.Chess.TILE_W;
import static chess.Chess.TILE_Y;
import javafx.scene.paint.Color;
import javafx.scene.shape.Rectangle;
public class Tile extends Rectangle{
private final int width = TILE_W;
private final int height = TILE_Y;
private final int x;
private final int y;
private Color color;
public void setColor(Color color) {
this.color = color;
}
public Color getColor(){
return this.color;
}
public Tile(Color c, int x, int y){
this.color = c;
this.x = x;
this.y = y;
setFill(c);
setHeight(this.height);
setWidth(this.width);
relocate(x*TILE_W, y*TILE_Y);
}
}
这是我的董事会课程：
package chess.Board;
import static chess.Chess.HEIGHT;
import static chess.Chess.TILE_W;
import static chess.Chess.TILE_Y;
import static chess.Chess.WIDTH;
import javafx.scene.Parent;
import javafx.scene.layout.GridPane;
import javafx.scene.paint.Color;
public class Board {
private Tile[][] tilesMatrix;
private void setMatrix(){
Tile[][] tilesCreator = new Tile[WIDTH][HEIGHT];
for(int y = 0; y < HEIGHT; y++){
for(int x = 0; x < WIDTH; x++){
if(y%2 == 0){
if(x%2 == 0)
tilesCreator[x][y] = new Tile(Color.ANTIQUEWHITE, x, y);
else
tilesCreator[x][y] = new Tile(Color.DARKGREEN, x, y);
}
else{
if(x%2 == 0)
tilesCreator[x][y] = new Tile(Color.DARKGREEN, x, y);
else
tilesCreator[x][y] = new Tile(Color.ANTIQUEWHITE, x, y);
}
}
}
this.tilesMatrix = tilesCreator;
}
public Tile[][] getMatrix(){
return this.tilesMatrix;
}
public Parent getBoard(){
GridPane board = new GridPane();
board.setPrefSize(WIDTH*TILE_W, HEIGHT*TILE_Y);
for(int y = 0; y < HEIGHT; y++)
for(int x = 0; x < WIDTH; x++)
board.add(getMatrix()[x][y], x, y);
return board;
}
public Board(){
setMatrix();
}
}
【问题讨论】：
标签： java javafx children gridpane