TypeError：升级到 django 1.5.1 后，“模块”对象不可下标答案

【问题标题】：TypeError: 'module' object is not subscriptable after upgrade to django 1.5.1TypeError：升级到 django 1.5.1 后，“模块”对象不可下标
【发布时间】：2013-07-22 13:06:55
【问题描述】：

从 django 1.2.7 升级到 1.5.1 后尝试使用

运行 celery 时

python manage.py celeryd -v 2 -l INFO --settings=settings

我有一个错误提示

django.core.management.execute_manager

在 django 1.4 中已弃用

我的manage.py

#!/usr/bin/env python
from django.core.management import execute_manager
try:
    import settings # Assumed to be in the same directory.
except ImportError:
    import sys
    sys.stderr.write("Error: Can't find the file 'settings.py' in the directory containing %r. It appears you've customized things.\nYou'll have to run django-admin.py, passing it your settings module.\n(If the file settings.py does indeed exist, it's causing an ImportError somehow.)\n" % __file__)
    sys.exit(1)

if __name__ == "__main__":
    execute_from_command_line(settings)

我查看了 django 1.4 发行说明

django-core-management-execute-manager

正如上面所说，我用 execute_from_command_line 替换了 execute_manager

现在我在重新启动服务器时开始收到此错误消息

Traceback (most recent call last):
  File "C:\my\manage.py", line 12, in <module>
    execute_from_command_line(settings)
  File "C:\Python27\lib\site-packages\django\core\management\__init__.py", line 452, in     execute_from_command_line
    utility = ManagementUtility(argv)
  File "C:\Python27\lib\site-packages\django\core\management\__init__.py", line 226, in __init__
    self.prog_name = os.path.basename(self.argv[0])
TypeError: 'module' object is not subscriptable

【问题讨论】：

标签： python django django-manage.py

【解决方案1】：

您将错误的参数传递给 execute_from_command_line 方法。您应该执行以下操作：

#!/usr/bin/env python
import os
import sys

if __name__ == "__main__":
    os.environ.setdefault("DJANGO_SETTINGS_MODULE", "<package>.<subpackage>.settings") #path to the settings py file
    from django.core.management import execute_from_command_line
    execute_from_command_line(sys.argv)

或

#!/usr/bin/env python
import os

if __name__ == "__main__":
    os.environ.setdefault("DJANGO_SETTINGS_MODULE", "<package>.<subpackage>.settings") #path to the settings py file
    from django.core.management import execute_from_command_line
    execute_from_command_line() # by default sys.argv argument is taken

确实，execute_from_command_line 的参数，顾名思义，是一个解析后的命令行，其中第一个元素是可执行文件名，其他元素是参数

【讨论】：