查询表达式中的语法错误（缺少运算符） - MS-Access答案

【问题标题】：Syntax Error(missing operator) in query expression - MS-Access查询表达式中的语法错误（缺少运算符） - MS-Access
【发布时间】：2010-12-19 23:39:30
【问题描述】：

这不会产生语法错误，但会给出错误的参数错误：

SELECT left(
  [aname],
 IIF(instr([aname], " ") = 0 AND instr([aname], ",") = 0,
   Len(FinalForgotten.aname),
  IIF(instr([aname], ",") = 0,
    InStr(1,[aname]," ")-1,
    InStr(1,[aname],",")-1)))
&  ","  &

right(
   [aname],
 IIF(instr([aname], " " = 0 AND instr([aname], ",") = 0,
   Len(FinalForgotten.aname),
    IIF(instr([aname], ",") = 0,
      Len(aname)-InStr(1,[aname]," "),
      Len(aname)-InStr(1,[aname],",")))))
 &  " " &

defense_final.middle_initial AS fullname INTO FinalForgottenWithMiddle
FROM FinalForgotten INNER JOIN defense_final ON (right(FinalForgotten.aname,
 IIF(instr([aname], ",") = 0,
 Len(FinalForgotten.aname)-InStr(1,FinalForgotten.[aname]," "),
 Len(FinalForgotten.aname)-InStr(1,FinalForgotten.[aname],",")
  )
 )=defense_final.first_name) AND (left(FinalForgotten.aname,
IIF(instr([aname], ",") = 0,
  InStr(1,FinalForgotten.[aname]," ")-1,
  InStr(1,FinalForgotten.[aname],",")-1
    )
)=defense_final.last_name);

添加额外的参数后，我现在得到语法错误“缺少 )、] 或查询表达式中的项目”：

   SELECT left(
  [aname],
 IIF(instr([aname], " ") = 0 AND instr([aname], ",") = 0,
   Len(FinalForgotten.aname),
  IIF(instr([aname], ",") = 0,
    InStr(1,[aname]," ")-1,
    InStr(1,[aname],",")-1)))
&  ","  &

right(
   [aname],
 IIF(instr([aname], " ") = 0 AND instr([aname], ",") = 0,
   Len(FinalForgotten.aname),
    IIF(instr([aname], ",") = 0,
      Len(aname)-InStr(1,[aname]," "),
      Len(aname)-InStr(1,[aname],","))))
 &  " " &

defense_final.middle_initial AS fullname INTO FinalForgottenWithMiddle
FROM FinalForgotten INNER JOIN defense_final ON 

left(FinalForgotten.aname,
   IIF(instr([aname], " ") = 0 AND instr([aname], ",") = 0,
      Len(FinalForgotten.aname),
      IIF(instr([aname], ",") = 0,
        InStr(1,FinalForgotten.[aname]," ")-1,
        InStr(1,FinalForgotten.[aname],",")-1)))

 =defense_final.last_name AND 

 right(FinalForgotten.aname,
      IIF(instr([aname], " ") = 0 AND instr([aname], ",") = 0,
      Len(FinalForgotten.aname),
       IIF(instr([aname], ",") = 0,
        Len(FinalForgotten.aname)-InStr(1,FinalForgotten.[aname]," "),
        Len(FinalForgotten.aname)-InStr(1,FinalForgotten.[aname],","))))

=defense_final.first_name;

有什么解决方法吗？

感谢您的回复。

【问题讨论】：

我可以建议您给您的表格一个短（1 个字母）别名，并更新您的问题吗？我认为这会使它更具可读性。
您提到“错误的参数错误”。你能指定错误吗？这通常发生在某个字段拼写错误时。
@iDevlop 它说“查询表达式中函数使用的参数数量错误'left（...”

标签： ms-access syntax operator-keyword

【解决方案1】：

将该逻辑放入 VBA 函数会更容易，因此您的查询看起来像这样

SELECT GetFullNameWithMiddle([aname]) AS fullname
INTO FinalForgottenWithMiddle
FROM FinalForgotten INNER JOIN defense_final
    ON GetLastName([aname])=defense_final.last_name
    AND GetFirstName([aname])=defense_final.first_name

既然你说你不想使用 VBA，那就试试这个吧。我附上了每个

InStr(x, y) = 0

在括号中，所以

IIf(InStr(x, y) = 0 AND InStr(p, q) = 0, g, h)

变成

IIf((InStr(x, y) = 0) AND (InStr(p, q) = 0), g, h)

进行该更改后，我可以切换到查询设计网格，这意味着 SQL 解析器喜欢它：

SELECT left(
    [aname],
    IIF((instr([aname], " ") = 0) AND (instr([aname], ",") = 0),
    Len(FinalForgotten.aname),
    IIF((instr([aname], ",") = 0),
    InStr(1,[aname]," ")-1,
    InStr(1,[aname],",")-1)))

    &  ","  &

right(
    [aname],
    IIF((instr([aname], " ") = 0) AND (instr([aname], ",") = 0),
    Len(FinalForgotten.aname),
    IIF((instr([aname], ",") = 0),
      Len(aname)-InStr(1,[aname]," "),
      Len(aname)-InStr(1,[aname],","))))

    &  " " &

defense_final.middle_initial AS fullname INTO FinalForgottenWithMiddle
FROM FinalForgotten INNER JOIN defense_final ON 

left(FinalForgotten.aname,
    IIF((instr([aname], " ") = 0) AND (instr([aname], ",") = 0),
    Len(FinalForgotten.aname),
    IIF((instr([aname], ",") = 0),
    InStr(1,FinalForgotten.[aname]," ")-1,
    InStr(1,FinalForgotten.[aname],",")-1)))

=defense_final.last_name AND 

right(FinalForgotten.aname,
    IIF((instr([aname], " ") = 0) AND (instr([aname], ",") = 0),
    Len(FinalForgotten.aname),
    IIF((instr([aname], ",") = 0),
    Len(FinalForgotten.aname)-InStr(1,FinalForgotten.[aname]," "),
    Len(FinalForgotten.aname)-InStr(1,FinalForgotten.[aname],","))))

=defense_final.first_name;

【讨论】：

不适合我。我对VB不太好。我希望坚持使用 sql。
VBA 环境在告诉您语法错误在哪里方面做得更好。并且执行您在此处执行的操作的 VBA 比您构建的 SQL 语句要简单得多。但各有各的。如果我必须使用 SQL 执行此操作，那么我将使用 LIKE 而不是 InStr（[aname] LIKE "* *" 将给出与InStr([aname], " ") > 0 相同的结果）。我在编辑您的查询时玩了一下，我认为您可能只需要确保到处都有括号。请参阅新编辑的答案以获取建议。

【解决方案2】：

第 10 行

right(

没有对应的右括号

【讨论】：

【解决方案3】：

SELECT left( [aname], 所以 [aname] 是一个文本字段。

 IIF(instr([aname], " ") = 0 AND instr([aname], ",") = 0,

如果此条件为真，您希望左字符串的长度为：

 FinalForgotten.aname,

这不是整数。你想要：

SELECT left(
  [aname],
 IIF(instr([aname], " ") = 0 AND instr([aname], ",") = 0,
   Len(FinalForgotten.aname),

【讨论】：

【解决方案4】：

 IIF(instr([aname], " " = 0 AND instr([aname], ",") = 0,

第 12 行应该是

 IIF(instr([aname], " ") = 0 AND instr([aname], ",") = 0,

【讨论】：

它仍然给出错误“Missing ), ], or Item in query expression"